Ask question

Ask question

All categories

3 years ago

11

Describe a pro and con of having a passenger in the car

1 answer:

Julli [10]3 years ago

6 0

Answer:

One pro of having a passenger is: they can be very aware and help you when things go awry. one con of having a passenger is they can be distracting and even harmful to the driver. Question 2Impaired drivers are one of the many risks drivers face on the Highway Transportation System.

Explanation:

Your welcome!!❤

You might be interested in

Which of the following tools might civil engineers use when designing roads in a recently constructed industrial park?

Dmitry [639]

Answer:D. Gunter's Chain

Explanation:I know this because a gunter's chain is used for plots of land to be accurately surveyed and plotted, for legal and commercial purposes.

6 0

4 years ago

Read 2 more answers

Dimension these please.

Svetach [21]

Answer:

86

Explanation:

3 0

3 years ago

Water flows with an average speed of 6.5 ft/s in a rectangular channel having a width of 5 ft The depth of the water is 2 ft.

lisov135 [29]

Answer:

specific energy = 2.65 ft

y2 = 1.48 ft

Explanation:

given data

average speed v = 6.5 ft/s

width = 5 ft

depth of the water y = 2 ft

solution

we get here specific energy that is express as

specific energy = y + $\frac{v^2}{2g}$ ...............1

put here value and we get

specific energy = $2 + \frac{6.5^2}{2\times 9.8\times 3.281}$

specific energy = 2.65 ft

and

alternate depth is

y2 = $\frac{y1}{2} \times (-1+\sqrt{1+8Fr^2})$

and

here Fr² = $\frac{v1}{\sqrt{gy}} = \frac{6.5}{\sqrt{32.8\times 2}}$

Fr² = 0.8025

put here value and we get

y2 = $\frac{2}{2} \times (-1+\sqrt{1+8\times 0.8025^2})$

y2 = 1.48 ft

7 0

3 years ago

An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after

KIM [24]

Answer:

The answer is below

Explanation:

a) The work done is equal to the loss in kinetic energy (KE)

Change in kinetic energy (ΔKE) = Final kinetic energy - initial kinetic energy

Final KE = $\frac{1}{2}mv_f^2$

But the final velocity is 0 (at rest). Hence:

Final KE = $\frac{1}{2}mv_f^2=\frac{1}{2}m(0)^2=0$

ΔKE = 0 - K = -K

W = ΔKE = -K

Also, the work done (W) = charge (q) * distance (d) * electric field intensity (E)

W = qEd

but q = -e, hence:

W = -e * E * d

Using:

W = ΔKE

-e * E * d = -K

E= K / (e * d)

b) The electric field is in the direction of the electrons motion

7 0

3 years ago

water at 20c discharges from a stroke tank through a 150m length of horizontal pipe. The pipe is smooth and has a diameter of 75

inessss [21]

Answer:

The dept of the water needed is 26.11m

Explanation:

Given the following parameters:

Length of the pipe = $150m$

Diameter of the pipe = $75mm = 0.75m$

Volumetric flow rate $1m^{3}/s$

Knowing that:

Volumetric flowrate $= area (A) * Velocity(V)$

==> $0.1 = A*V$ *Knowing that $V = \sqrt{2gh}$

==> $0.1 = \frac{\pi }{4}* (0.075)^{2} * \sqrt{2gh}$

==> $h = 26.11m$

Hence, the dept of water needed to produce a volumetric flow rate of $1m^{3}/s$ is 26.11m.

7 0

3 years ago