Answer:
M_c = 61.6 Nm
Explanation:
Given:
F_a = 2.5 KN
Find:
Determine the moment of this force about C for the two casesshown.
Solution:
- Draw horizontal and vertical vectors at point A.
- Take moments about point C as follows:
M_c = F_a*( 42 / 150 ) *88
M_c = 2.5*( 42 / 150 ) *88
M_c = 61.6 Nm
- We see that the vertical component of force at point A passes through C.
Hence, its moment about C is zero.
Answer:
A. National Highway Safety Act
Explanation:
The National Highway Safety Act establishes general guidelines concerning licensing, vehicle registration and inspection, and traffic laws for state regulations. The act was made in 1966 to reduce the amount of death on the highway as a result of increase in deaths by 30% between 1960 and 1965
National Traffic and Motor Vehicle Safety Act regulates vehicle manufacturers by ensuring national safety standards and issuance recalls for defective vehicles
Uniform Traffic Control Devices Act defines shapes, colors and locations for road signs, traffic signals, and road markings
The load is 17156 N.
<u>Explanation:</u>
First compute the flexural strength from:
σ = FL / π
= 3000
(40
10^-3) / π (5
10^-3)^3
σ = 305
10^6 N / m^2.
We can now determine the load using:
F = 2σd^3 / 3L
= 2(305
10^6) (15
10^-3)^3 / 3(40
10^-3)
F = 17156 N.
Answer:
The picture below with the answer. Hope it helps, have a great day/night and stay safe! Length of the coil,