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3 years ago

How can feeding plant crops to animals be considered an efficient use of those crops?

Engineering

1 answer:

stira [4]3 years ago

7 0

Answer:

Most of Our Grain is Being Consumed by Animals, Not Humans. How the Planting of Crops Used to Feed Livestock is Contributing to Habitat Destruction.

Explanation:

The major feed grains are corn, sorghum, barley, and oats.

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What does basic levels of competence involves??

strojnjashka [21]

UnconsciousIncompetence = you don't know that you can't do it well.
ConsciousIncompetence = you know you can't do it well.
ConsciousCompetence = you do it well, and you think about the work as you do it.
UnconsciousCompetence = you're so successful it's "automatic" -- you do it well, without thinking about it.

6 0

3 years ago

Read 2 more answers

A conical enlargement in a vertical pipeline is 5 ft long and enlarges the pipe diameter from 12 in. to 24 in. diameter. Calcula

makkiz [27]

Answer:

F_y = 151319.01N = 15.132 KN

Explanation:

From the linear momentum equation theory, since flow is steady, the y components would be;

-V1•ρ1•V1•A1 + V2•ρ2•V2•A2 = P1•A1 - P2•A2 - F_y

We are given;

Length; L = 5ft = 1.52.

Initial diameter;d1 = 12in = 0.3m

Exit diameter; d2 = 24 in = 0.6m

Volume flow rate of water; Q2 = 10 ft³/s = 0.28 m³/s

Initial pressure;p1 = 30 psi = 206843 pa

Thus,

initial Area;A1 = π•d1²/4 = π•0.3²/4 = 0.07 m²

Exit area;A2 = π•d2²/4 = π•0.6²/4 = 0.28m²

Now, we know that volume flow rate of water is given by; Q = A•V

Thus,

At exit, Q2 = A2•V2

So, 0.28 = 0.28•V2

So,V2 = 1 m/s

When flow is incompressible, we often say that ;

Initial mass flow rate = exit mass flow rate.

Thus,

ρ1 = ρ2 = 1000 kg/m³

Density of water is 1000 kg/m³

And A1•V1 = A2•V2

So, V1 = A2•V2/A1

So, V1 = 0.28 x 1/0.07

V1 = 4 m/s

So, from initial equation of y components;

-V1•ρ1•V1•A1 + V2•ρ2•V2•A2 = P1•A1 - P2•A2 - F_y

Where F_y is vertical force of enlargement pressure and P2 = 0

Thus, making F_y the subject;

F_y = P1•A1 + V1•ρ1•V1•A1 - V2•ρ2•V2•A2

Plugging in the relevant values to get;

F_y = (206843 x 0.07) + (1² x 1000 x 0.07) - (4² x 1000 x 0.28)

F_y = 151319.01N = 15.132 KN

6 0

3 years ago

The flowrate through a rectangular channel is 20 cfs. The upstream width of the channel is 10 ft, and the depth of the water in

Liula [17]

To solve this problem we will use the Froude number that relates the Forces of Inertia with the Forces of Gravity. There will be jump in the downstream only if Froude Number (Fr) is greater than 1 at upstream. Our values are given as,

$Q = 20cfs\\w= 10ft\\D= 1ft$

Then the velocity would be:

$V = \frac{Q}{wD}V = \frac{20}{10*1}V = 2ft/s$

The number of Froude is given as,

$Fr = \frac{V}{gD}^{1/2}$

Where,

V = Velocity

g = Gravity

D = Diameter

Replacing we have that

$Fr = \frac{2}{32.2}^{1/2}\\Fr = 0.352\\Fr$

There will be no Jump, correct answer is B.

5 0

3 years ago

piston-cylinder assembly contains water vapor, initially at 10 bar and 360 degC. The water undergoes a process where pv=constant

DIA [1.3K]

Answer:

Check the explanation

Explanation:

A diagrams showing the process in p-v and T-s and the Model engineering <u><em>(which is the quest in constructing miniature working representations of proportionally-scaled in full-sized machines. It is a subdivision of metalworking with a sharp importance on artisanry, in contrast to mass production.)</em></u> can be seen in the attached images below.

3 0

3 years ago

In a lab, scientists grew several generations of offspring of a plant using the method shown. What conclusion can you make about

exis [7]

Answer: c) they have low genetic variability among them.

When a plant is grown for several generations of offspring of a plant, then there are some common things which are to be noted which are found similar in the offspring and in the parent of the offspring. The flowers and fruits and the time or season they come in are absolutely the same.

6 0

1 year ago