9th value is 34
Explanation:
R or Fib (n) function is given by: (n - 1) + (n - 2), where n is the number in the Fibonacci sequence
.
Hence, fib (9) = (9 - 1) + (9 - 2)
= 8th value + 7th value on the sequence summed together
<em>Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21.</em><em> </em>The 8th value is 21 and the 7th value is 13.
R = (n - 1) + (n - 2)
R (9) 0r Fib (9) = 21 + 13
= 34
Answer:
We have to remember that being an engineer is a very high performing job, if only a tiny aspect is ruined, the whole operation is ruined and it shuts down.
Many engineers work on one aspect of something, it could be a building or a machine. If you do not communicate with the other people, then whatever you're working on will collapse, or not get done at all.
Lets say one guy put a steel beam on one side of a wall, and another guy put a wooden plank on the other side of the wall, but all this time the wall was supposed to be made of concrete bricks.
The whole thing would just collapse and be ruined. Communication and listening to inctructions is key.
Answer:
Correct sentence: (c) more.
Explanation:
Otto cycle:
An ideal Otto cycle models the behavior of an explosion engine. This cycle consists of six steps, as indicated in the figure. Prove that the performance of this cycle is given by the expression
η = 1 - (1/r^(ρ-1))
where r = VA / VB is the compression ratio equal to the ratio between the volume at the beginning of the compression cycle and at the end of it. ρ=1.4
Diesel cycle:
The ideal Diesel cycle is distinguished from the ideal Otto in the combustion phase, which in the Otto cycle is assumed at a constant volume and in the Diesel at constant pressure. Therefore the performance is different.
If we write the performance of a Diesel cycle in the form
:
η = 1 - (1/r^(ρ-1)) × ( (r^ρ)-1)/(ρ^(r-1)) )
we see that the efficiency of a Diesel cycle differs from that of an Otto cycle by the factor in parentheses. This factor is always greater than the unit, therefore, for the same compression reasons r
diesel performance is less than otto performance
\ eta_ \ mathrm {Diesel} <\ eta_ \ mathrm {Otto} \,
Answer:
Correct option a) True.
Explanation:
It is true since the Vickers hardness value refers to the force applied in a 136 ° diamond tip penetrator divided by the surface of the groove produced in the material, the lower the impression made on this greater the value will be end of the Vickers measurement and greater its hardness.
The equation to determine the Vickers hardness value will be:
Hv= ((1.854 × P)/(d²)) (kg/mm²)
Therefore a value of 220 Vickers refers to a harder material than another value of 180 Vickers.
