Question

How many molecules are present in 4.21 moles of HBr?​

Answer 1

Answer:

The answer is

2.53 × 10²⁴ molecules

Explanation:

The number of molecules present can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.21 × 6.02 × 10²³

We have the final answer as

2.53 × 10²⁴ molecules

Hope this helps you