Answer:
Mg²⁺(aq) + SO₃²⁻(aq) + 2 H⁺(aq) + 2 I⁻(aq) ⇄ Mg²⁺(aq) + 2I⁻(aq) + H₂O(l) + SO₂(g)
Explanation:
<em>Give the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of MgSO₃ and HI are mixed.</em>
When MgSO₃ reacts with HI they experience a double displacement reaction, in which the cations and anions of each compound are exchanged, forming H₂SO₃ and MgI₂. At the same time, H₂SO₃ tends to decompose to H₂O and SO₂. The complete molecular equation is:
MgSO₃(aq) + 2 HI(aq) ⇄ MgI₂(aq) + H₂O(l) + SO₂(g)
In the complete ionic equation, species with ionic bonds dissociate into ions.
Mg²⁺(aq) + SO₃²⁻(aq) + 2 H⁺(aq) + 2 I⁻(aq) ⇄ Mg²⁺(aq) + 2I⁻(aq) + H₂O(l) + SO₂(g)
The correct answer is the atomic radius increase because of the higher number of occupied energy levels.
Atomic radius increases when going down a group. The valence electrons hold the higher levels because of the enhancing quantum number (n). As a consequence, the valence electrons get further away from the nucleus with the increase in n. The electron shielding inhibits these outer electrons from getting fascinated towards the nucleus. Therefore, they are held, and the resulting atomic radius is greater.
CL
Chlorine<span>
</span>You wiil find in periodic table :)
Answer:
The equation shows balance.
Explanation:
You can easily count the number of elements on each side.
On the left side of the equation, you have 2 moles of Na and 2 moles of Cl.
On the right side of the equation, you also have 2 moles of Na and 2 moles of Cl because the two elements formed a compound meaning that whatever number is in front of them, both elements will receive the same number.
The compound that has the smallest ions with the greatest charge will have the strongest ionic bonds. On the other hand, large and minimally charged ions will form weaker bonds.
