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Virty [35]
3 years ago
10

How many molecules are present in 4.21 moles of HBr?​

Chemistry
1 answer:
salantis [7]3 years ago
6 0

Answer:

The answer is

<h3>2.53 × 10²⁴ molecules</h3>

Explanation:

The number of molecules present can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.21 × 6.02 × 10²³

We have the final answer as

<h3>2.53 × 10²⁴ molecules</h3>

Hope this helps you

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If 20.0 mL of a 0.0800 M HNO3, 35.0 mL of a 0.0800 M KSCN, and 40.0 mL of a 0.0800 M Fe(NO3)3 are combined, what is the initial
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Answer:

0.0295M

Explanation:

As you can see, in the mixture you have KSCN and other compounds. The KSCN in solution is dissolved in K⁺ ions and SCN⁻ ions. That means initial concentration of SCN⁻ ions is the same of KSCN, 0.0800M.

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<h3>0.0295M </h3>

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