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melisa1 [442]
3 years ago
7

How many mL of a 1 M NaOH solution are required to neutralize 100 mL of a 2 M H2SO4 solution?

Chemistry
1 answer:
Murljashka [212]3 years ago
5 0

Answer : The volume of 1 M NaOH solution required are, 400 mL

Explanation :

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=2M\\V_1=100mL\\n_2=1\\M_2=1M\\V_2=?

Putting values in above equation, we get:

2\times 2M\times 100mL=1\times 1M\times V_2

V_2=400mL

Therefore, the volume of 1 M NaOH solution required are, 400 mL

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Explanation:

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An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

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