Question

How many mL of a 1 M NaOH solution are required to neutralize 100 mL of a 2 M H2SO4 solution?

Answer 1

Answer : The volume of 1 M NaOH solution required are, 400 mL

Explanation :

To calculate the volume of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=2M\\V_1=100mL\\n_2=1\\M_2=1M\\V_2=?$

Putting values in above equation, we get:

$2\times 2M\times 100mL=1\times 1M\times V_2$

$V_2=400mL$

Therefore, the volume of 1 M NaOH solution required are, 400 mL