Ask question

Ask question

All categories

3 years ago

5

A bag contains ten marbles of equal size and weight. One marble is blue, one marble is white, three are yellow, and five marbles

are red. A marble is taken from the bag two times. Each time a marble is taken out, it is not replaced. What is the probability of picking a blue marble and picking a white marble? A) 1/100 B) 1/5 C) 1/90 D) 2/15

1 answer:

Andrej [43]3 years ago

4 0

Itz B because 10-2=8
It would be like this 2/10 (btw it's not division...is a fraction) simplified to 1/5

You might be interested in

It costs 3 tickets to play a game at the fair. If you spent 21tickets on the game, which equation could you use to solve for the

solniwko [45]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ The correct option would be D. 3g = 21

As it is 3 tickets per game, the total number of tickets would be 3 multiplied by the number of games

This equation could then be rearranged to find the number of games.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

5 0

2 years ago

Read 2 more answers

Convert the degrees measure 180° to radian measure.

Mandarinka [93]

180° = 3.1415926536 rad

4 0

3 years ago

Read 2 more answers

If Erin built a rectangular prism shaped trough for her horses to eat from the trough is 3 m long 1 m wide and 1 m high hay for

telo118 [61]

It would cost $33.00 hope that helps

3 0

3 years ago

How are percent error and percent change similar

mihalych1998 [28]

Percent Change = New Value − Old Value|Old Value| × 100%

Example: There were 200 customers yesterday, and 240 today:

240 − 200|200|× 100% = 40200 × 100% = 20%

A 20% increase.

Percent Error = |Approximate Value − Exact Value||Exact Value| × 100%

Example: I thought 70 people would turn up to the concert, but in fact 80 did!

|70 − 80||80| × 100% = 1080 × 100% = 12.5%

I was in error by 12.5%

(Without using the absolute value, the error is −12.5%, meaning I under-estimated the value)

The difference between the two is that one states factual calculations and the other is a theoretical guess

5 0

2 years ago

A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

2 years ago