Answer:
B: Na(s) + Cl2(g) + 3O2(g) = 2NaClO3(s)
Explanation:
We are looking for enthalpy of formation, so we want to see reactance in their natural standard form.
Thus, we want to see the reactance of Na, Cl2 and O2.
The only option that has the correct form of Na, Cl2 and O2 is B.
Na(s) + Cl2(g) + 3O2(g) = 2NaClO3(s)
Ag203 (Nh4)2co3 solution is Added to 79.8mL
Answer:
The routes are in the attached figure bellow.
Explanation:
In order to have a nucleophilic substituition, we need a substract with a positive or partially positive carbon. Therefore, the two possible substracts chosen were alkyl halides. The chlorine is more electronegative than the carbon, therefore the electronic density will be deslocated towards the Cl atom an the C atom will be left partially positive.
The nucleophiles given have strong negative charges and will attack the partially positive carbon. The chlorine will then leave the molecule (leaving group) and a new bond between the carbon and the oxigen will be formed.
Both routes will involve a Sn2 mechanism, which means that the reactions will occur in one step.
Answer:
any salt
sodium chloride
callcium chloride
potassium chloride
Explanation:
There is no general effect of temperature on the solubility of salts.effect of increase temperature on the solubilty of NaCl is not significant because it is more soluble even at low temperature. The salt like potassium iodide (KI) has negative heat of solution so it's solubility decreases with increase of temperature…
Answer:
B. Distance from earth. I'm pretty sure. From what I learned it should be that.