Answer:
It will take 313.376 sec to raise temperature to boiling point
Explanation:
We have given that potential difference V = 120 Volt
Current i = 4.50 A
So resistance 
Heat flow in resistor will be equal to 
It is given that this heat is used for boiling the water
Mass of the water = 0.525 kg = 525 gram
Specific heat of water 4.186 J/gram/°C
Initial temperature is given as 23°C
Boiling temperature of water = 100°C
So change in temperature = 100-23 = 77°C
Heat required to raise the temperature of water 
So 
t = 313.376 sec
So it will take 313.376 sec to raise temperature to boiling point
Answer:
Explanation: the major difference between an electromagnet and permanent magnet is that the former can have a magnetic field when electric current flows through it and disappears when the flow of the current stops. ... It will always displays the magnetic behaviour.
Answer:
Friction between the box and the floor is 25N to the left.
Explanation:
According to Newton's second law of motion, the net force acting on an object is equal to the produce between the object's mass and its acceleration:

where
m is the mass of the object
a is its acceleration
In this problem, we have two forces acting on the object:
- The applied force, F = 25 N, to the right
- The force of friction
, opposing the motion of the box, so to the left
So we can write the net force as

Also, we know that the box is moving at constant speed: this means its acceleration is zero, so

Therefore

WHich means:

And therefore,

which means that the force of friction is also 25 N.
The resistance is 4 times the resistance of the first wire. the formula is R = p*l/A with p being resistivity, l length and A area. So if you double length and half area, which botv result in more resistance, you get p*2/0.5 or 4 (p can be abandoned because it is the same. We take standard length and area as 1)
Answer:
a)1.51*10^-22joules b) 1.89*10^-7m
Explanation:
Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules
b) net force acting to stop the proton = 8.01*10^-16
Work done needed to stop the proton = net force acting opposite the motion * distance
Distance covered = need work done/ net force
Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m