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kaheart [24]
4 years ago
12

Question 1 of 10 What is molarity a measurement of? O A. The volume of liquid containing a dissolved substance B. The grams of a

substance dissolved in a liquid O c. The concentration of a substance dissolved in a liquid O D. The number of moles of a dissolved substance
​
Chemistry
2 answers:
Mama L [17]4 years ago
8 0

To do this measure called molarity is commonly used. Molarity (M) is defined as the number of moles of solute (n) divided by the volume (V) of the solution in liters. It is important to note that the molarity is defined as moles of solute per liter of solution, not moles of solute per liter of solvent.                    

so the answer is D.

hope this helps have a great day....!

Nuetrik [128]4 years ago
7 0

Answer:

D

Explanation:

D. The number of moles of a dissolved substance

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What happens to a substance when it dissolves​
uranmaximum [27]

Answer:

A solution is made when one substance called the solute "dissolves" into another substance called the solvent.

Explanation:

once it is broken down"dissolves" from bigger pieces it becomes much smaller groups

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3 years ago
Identify indicators of a chemical reaction. Check all of the boxes that apply.
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All except for absorption of heat
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1 year ago
The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.13 M, it takes ________ min for
Zigmanuir [339]

Answer:

Therefore it takes 8.0 mins for it to decrease to 0.085 M

Explanation:

First order reaction: The rate of reaction is proportional to the concentration of reactant of power one is called first order reaction.

A→ product

Let the concentration of A = [A]

\textrm{rate of reaction}=-\frac{d[A]}{dt} =k[A]

k=\frac{2.303}{t} log\frac{[A_0]}{[A]}

[A₀] = initial concentration

[A]= final concentration

t= time

k= rate constant

Half life: Half life is time to reduce the concentration of reactant of its half.

t_{\frac{1}{2} }=\frac{0.693}{k}

Here t_{\frac{1}{2} }=0.13 min

k=\frac{0.693}{t_{\frac{1}{2}} }

\Rightarrow k=\frac{0.693}{13 }

To find the time takes for it to decrease to 0.085 we use the below equation

k=\frac{2.303}{t} log\frac{[A_0]}{[A]}

\Rightarrow t=\frac{2.303}{k} log\frac{[A_0]}{[A]}

Here ,   k=\frac{0.693}{13 },  [A₀] = 0.13 m and [ A] = 0.085 M

t=\frac{2.303}{\frac{0.693}{13} } log(\frac{0.13}{0.085})

\Rightarrow t= 7.97\approx 8.0

Therefore it takes 8.0 mins for it to decrease to 0.085 M

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3 years ago
Can someone help me balance these chemical equations?
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Explanation:

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3 0
3 years ago
Read 2 more answers
20.
sergiy2304 [10]
I think the anwser is A
8 0
3 years ago
Read 2 more answers
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