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2 years ago

What determines the period of a pendulum?

Physics

2 answers:

cupoosta [38]2 years ago

8 0

The length of the pendulum and the acceleration of gravity determine the period of a pendulum.

<u>Explanation: </u>

We all are familiar with the pendulum and its motion. The way it swings from its rest position to the left and right ends with specific amplitude.

A pendulum can be simply defined as an object hung of a static point with a bob connected to it through a string.

When the bob is raised to the either direction from its rest position, it swings back and forth because of the acceleration (g). A complete back and forth swing of a bob from its rest position in the pendulum is counted as one complete period of a pendulum.

This primarily depends on length and acceleration. For simple pendulums, formula to evaluate its period is,

$T=2 \pi \sqrt{\frac{L}{g}}$

Where,

L- length of the string from the static suspension point to the bob in the pendulum

g- Acceleration due to gravity = 9.8 $m / s^{2}$

Inessa05 [86]2 years ago

6 0

The length of the string must vary, while the angle and acceleration are constant

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2 years ago

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ANSWER ASAP!!!If a wave machine produces 10 waves in 2 seconds, what is the frequency of the machine in Hertz?

Rufina [12.5K]

Answer:

5Hz

Explanation:

Frequency = No. of waves per second

10 waves are produced in 2 seconds

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2 years ago

________ can occur when an analog connection creates an electromagnetic field around its conductors, inducing its waveforms on a

KatRina [158]

Answer:

Crosstalk

Explanation:

The answer is Crosstalk as this phenomenon is most commonly associated with analog phone call.

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2 years ago

A block is at rest on a plank whose angle can be varied. The angle is gradually increased from 0 deg. At 31.8°, the block starts

galina1969 [7]

Answer:

$\mu_s = 0.62$

$\mu_k = 0.415$

The motion of the block is downwards with acceleration 1.7 m/s^2.

Explanation:

First, we will calculate the acceleration using the kinematics equations. We will denote the direction along the incline as x-direction.

$x - x_0 = v_0t + \frac{1}{2}at^2\\3.4 = 0 + \frac{1}{2}a(2)^2\\a = 1.7~m/s^2$

Newton’s Second Law can be used to find the net force applied on the block in the -x-direction.

$F = ma\\F = 1.7m$

Now, let’s investigate the free-body diagram of the block.

Along the x-direction, there are two forces: The x-component of the block’s weight and the kinetic friction force. Therefore,

$F = mg\sin(\theta) - \mu_k mg\cos(\theta)\\1.7m = mg\sin(31.8) - \mu_k mg\cos(31.8)\\1.7 = (9.8)\sin(\theta) - mu_k(9.8)\cos(\theta)\\mu_k = 0.415$

As for the static friction, we will consider the angle 31.8, but just before the block starts the move.

$mg\sin(31.8) = \mu_s mg\cos(31.8)\\\mu_s = tan(31.8) = 0.62$

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2 years ago

Imagine holding a basketball in both hands, throwing it straight up as high as you can, and then catching it when it falls. At w

Alisiya [41]

Answer:

C. At the instant the ball reaches its highest point.

Explanation:

When a body is thrown up, it tends to come down due to the influence of gravitational force acting on the body. The body will be momentarily at rest at its maximum point before falling. At this maximum point, the velocity of the body is zero and since force acting on a body is product of the mass and its acceleration, the force acting on the body at that point will be "zero"

Remember, F = ma = m(v/t)

Since v = 0 at maximum height

F = m(0/t)

F = 0N

This shows that the force acting on the body is zero at the maximum height.

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2 years ago