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Neporo4naja [7]
3 years ago
15

When an object oscillating in simple harmonic motion is at its maximum displacement from the equilibrium position, which of the

following is true of the values of its speed and the magnitude of the restoring force?
Speed: Magnitude of Restoring Force:

A .Zero Zero
B.1/2 Maximum 1/2 Maximum
C. Maximum Zero
D. Maximum 1/2 Maximum
E. Zero Maximum
Physics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

E. Zero Maximum

Explanation:

At the point of maximum displacement, the speed is zero while the restoring force is maximum. In fact:

- The restoring force is given by F=kx, where k is the spring constant and x is the displacement - at the point of maximum displacement, x is maximum, so F is maximum as well

- the total energy of the system is sum of kinetic energy and elastic potential energy:

E=K+U=\frac{1}{2}mv^2+\frac{1}{2}kx^2

where m is the mass of the system and v is the speed. Since E (the total energy) is constant due to the law of conservation of energy, we have that when K increases, U decreases, and viceversa. As a result, when x increases, v decreases, and viceversa. At the point of maximum displacement, x is maximum, so v will have its minimum value (which is zero, since the system is changing direction of motion).

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Explanation:

The parameters given are

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Before the man jumps, he will be experiencing potential energy at the top of the table.

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Substitute all the parameters into the formula

P.E = 60 × 9.8 × 0.8

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As he jumped from the table and hit the ground, the whole P.E will be converted to kinetic energy according to conservative of energy.

When hitting the ground,

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V = square root (15.68)

V = 3.959 m/s

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