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Neporo4naja [7]
4 years ago
15

When an object oscillating in simple harmonic motion is at its maximum displacement from the equilibrium position, which of the

following is true of the values of its speed and the magnitude of the restoring force?
Speed: Magnitude of Restoring Force:

A .Zero Zero
B.1/2 Maximum 1/2 Maximum
C. Maximum Zero
D. Maximum 1/2 Maximum
E. Zero Maximum
Physics
1 answer:
ziro4ka [17]4 years ago
4 0

Answer:

E. Zero Maximum

Explanation:

At the point of maximum displacement, the speed is zero while the restoring force is maximum. In fact:

- The restoring force is given by F=kx, where k is the spring constant and x is the displacement - at the point of maximum displacement, x is maximum, so F is maximum as well

- the total energy of the system is sum of kinetic energy and elastic potential energy:

E=K+U=\frac{1}{2}mv^2+\frac{1}{2}kx^2

where m is the mass of the system and v is the speed. Since E (the total energy) is constant due to the law of conservation of energy, we have that when K increases, U decreases, and viceversa. As a result, when x increases, v decreases, and viceversa. At the point of maximum displacement, x is maximum, so v will have its minimum value (which is zero, since the system is changing direction of motion).

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Newton's First and Second Laws of Motion:Question 3Kepler-10b, the first confirmed terrestrial extrasolar planet, is about 564 l
OleMash [197]

Answer:

F = 85696.5 N = 85.69 KN

Explanation:

In this scenario, we apply Newton's Second Law:

Unbalanced\ Force = ma\\Upthrust - Weight\ of\ Space\ Craft = ma\\F - W = ma\\F - mg = ma\\F = m(g + a)\\

where,

F = Upthrust = ?

m = mass of space craft = 5000 kg

g = acceleration due to gravity on surface of Kepler-10b = (1.53)(9.81 m/s²)

g = 15.0093 m/s²

a = acceleration required = 2.13 m/s²

Therefore,

F = (5000\ kg)(15.0093\ m/s^{2} + 2.13\ m/s^{2})\\

<u>F = 85696.5 N = 85.69 KN</u>

8 0
3 years ago
An arctic fox has thick, dense fur in the winter and much shorter fur in the summer. How does this help the fox maintain homeost
Sonja [21]
The increased thickness of the fox's fur allows the fox to warmer in cold temperatures, while the shorter fur does the opposite.
4 0
4 years ago
Read 2 more answers
Two mating steel spur gears are 20 mm wide, and the tooth profiles have radii of curvature at the line of contact of 10 and 15 m
Rom4ik [11]

Answer:

a) The maximum contact pressure is 274.58 MPa and the width of contact is 0.058 mm

b) The maximum shear stress is 82.37 MPa at a distance of 0.023 mm

Explanation:

Given data:

L = 20 mm

F = 250 N

r₁ = 10 mm

r₂ = 15 mm

v = 0.3

E = 2.07x10⁵ MPa

A=\frac{1-V_{1}^{2}  }{E_{1} }-\frac{1-V_{2}^{2}  }{E_{2} } =\frac{1-0.3^{2} }{2.07x10^{5} } *2=8.79x10^{-6}

a) The maximum contact pressure is:

P=0.564*\sqrt{\frac{F*(\frac{1}{r_{1} }+\frac{1}{r_{2} })  }{LA} } =0.564*\sqrt{\frac{250*(\frac{1}{10} +\frac{1}{15} )}{20*8.79x10^{-6} } } =274.58MPa

The width of contact is:

b=1.13*\sqrt{\frac{FA}{L(\frac{1}{r_{1} }+\frac{1}{r_{2} })  } } =1.13*\sqrt{\frac{250*8.79x10^{-6} }{20*(\frac{1}{10} +\frac{1}{15} )} } =0.029mm\\2*b=0.058mm

b) According the graph elastic stresses below the surface, for v = 0.3, the maximum shear stress is

T = 0.3*P = 0.3 * 274.58 = 82.37 MPa

At a distance of

0.8*b = 0.8*0.029 = 0.023 mm

6 0
3 years ago
The Voltage difference of a circuit is 16V and the resistance is 120 ohms. What is the current in the circuit? Show me your work
Ganezh [65]

Answer:

0.133 A

Explanation:

Given:

The voltage difference is, V=16\ V

The resistance of the circuit is, R=120\ ohms

Now, as per Ohm's Law, the potential difference across two points in a circuit is directly proportional to the current supplied in the circuit. The constant of proportionality is the resistance of the circuit.

Hence, the mathematical statement of Ohm's law is given as:

V=IR Where I is the current in the circuit.

Now, plug in 16 for 'V' and 120 for 'R' and solve for 'I'. This gives,

16=120I\\I=\frac{16}{120}\\I=0.133\ A

Therefore, the current in the circuit is 0.133 amperes.

7 0
3 years ago
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masha68 [24]
The waves as it gets closer
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