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kkurt [141]
3 years ago
5

A slice of cheese has a mass of 14 g and a volume of 11 cm3. What is the density of the cheese in units of g/cm3 and g/mL

Chemistry
1 answer:
cluponka [151]3 years ago
4 0

Answer:

Density =1.27g/cm

Explanation:

Density is the mass per volume of a substance.

That is

Density = mass/volume

Given that mass = 14g

Volume  = 11cm³

Therefore

Density = 14/11 g/cm³

Density =1.27g/cm³

I hope this was helpful, please mark as brainliest

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olya-2409 [2.1K]

Answer:

hope this answer will help you.

6 0
3 years ago
Aluminum reacts with a certain nonmetallic element to form a compound with the general formula AlX. Element X is a diatomic gas
Sergio039 [100]

Answer:

It's nitrogen

Explanation:

cuz it has valence 3 and  a diatomic gas at room temperature

5 0
3 years ago
A student finds that the water's temperature went from 18oC to 38oC. Calculate how many calories are in the peanut.
Norma-Jean [14]

Answer:

567 calories.

Explanation:

There 567 calories in 100 grams of peanut. In 100 grams of peanut, 49 gram is the fat, 26 grams of protein, 16 grams of carbohydrates, Sodium is 18 mg, Potassium is 705 mg. Calcium is present in peanut about 9%, Iron is 25% , Vitamin B-6 is 15%  and Magnesium is 42% of their total weight. Oil content is high in the Peanut so this is the reason for high calories in peanut. It is a good source of proteins and potassium.

4 0
3 years ago
A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in
In-s [12.5K]

Answer:

3.6667

Explanation:

<u>For helium gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.0 L

V₂ = 9.0 L

P₁ = 5.6 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{5.6}\times {3.0}={P_2}\times {9.0} atm

{P_2}=\frac {{5.6}\times {3.0}}{9.0} atm

{P_1}=1.8667\ atm

<u>The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm</u>

<u>For Neon gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{3.6}\times {4.5}={P_2}\times {9.0} atm

{P_2}=\frac {{3.6}\times {4.5}}{9.0} atm

{P_1}=1.8\ atm

<u>The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm</u>

<u>Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.</u>

6 0
3 years ago
Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1
kari74 [83]

Answer:

\boxed {\boxed {\sf 56 \ Joules}}

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

q=mc \Delta T

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C

q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)

Multiply the first numbers. The grams will cancel.

q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )

Multiply again. This time the degrees Celsius cancel.

q= 56 \ J

56 Joules of heat are needed.

4 0
3 years ago
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