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LenaWriter [7]
3 years ago
8

An Amtrak going 250m/s comes to a stop in 12s. What is the acceleration?

Physics
1 answer:
astraxan [27]3 years ago
7 0

Answer:

a=\frac{v-u}{t}  \\a = \frac{0-250}{12} = -20.83 m/s

Explanation:

you mean deceleration right ? because the acceleration is 250m/s

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Haley is trying to pull an object upward. The below forces are acting on the object.
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For this case, the first thing we must do is define a reference system.

Suppose that the positive direction of the reference system is upward.

We have that the sum of forces in the vertical axis is given by:

Fy = Fp - Fg

Substituting values:

Fy = 5500 - 6000

Fy = - 500

The negative sign means that the direction of the force with respect to the defined coordinate system is downward.

Answer:

The net force is:

↓ 500N

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3 years ago
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How does Mr. Anderson define solubility in the video?
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Answer:

7.3

Explanation:

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3 years ago
A 30-km, 34.5-kV, 60-Hz, three-phase line has a positive-sequence series impedance z 5 0.19 1 j0.34 V/km. The load at the receiv
zmey [24]

Answer:

(a) With a short line, the A,B,C,D parameters are:

    A = 1pu    B = 1.685∠60.8°Ω    C = 0 S    D = 1 pu

(b) The sending-end voltage for 0.9 lagging power factor is 35.96 KV_{LL}

(c) The sending-end voltage for 0.9 leading power factor is 33.40 KV_{LL}

Explanation:

(a)

Considering the short transition line diagram.

Apply kirchoff's voltage law to the short transmission line.

Write the equation showing the relations between the sending end and the receiving end quantities.

Compare the line equations with the A,B,C,D parameter equations.

(b)

Determine the receiving-end current for 0.9 lagging power factor.

Determine the line-to-neutral receiving end voltage.

Determine the sending end voltage of the short transition line.

Determine the line-to-line sending end voltage which is the sending end voltage.

(c)

Determine the receiving-end current for 0.9 leading power factor.

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8 0
3 years ago
You are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distan
Setler79 [48]

Answer:

25.52 m

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v_r=2.85-1.09=1.76\ m/s

Time taken by me to walk up to the person = 14.5 s

Distance is given by

Distance=Speed\times Time\\\Rightarrow s=vt\\\Rightarrow s=1.76\times 14.5\\\Rightarrow s=25.52\ m

The person was 25.52 m ahead of me when I started running

5 0
3 years ago
I don’t know where each one goes
Usimov [2.4K]
I classified them by numbers 1 to 8
Force: #s 2,4,5,67
Friction: #s 1 3 8
That’s it what I would say its the answer
3 0
2 years ago
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