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Bumek [7]
3 years ago
6

Why are the elements fluorine (F) , chlorine (Cl) , and bromine (Br) all found in the same group within the periodic table? A) T

hey all exist as gases at 20°C) . B) They all react with the noble gases. C) They have the same chemical properties. D) They are all non-metals that form 1+ ions.
Chemistry
2 answers:
Sergio039 [100]3 years ago
6 0
Fluorine, Chlorine, Bromine, Iodine and Astatine are representing the family of elements called : halogens.
Halogens:
- all have 7 electrons in their outer shell,
- are very reactive elements,
- form - 1 ions.
Answer: C ) They have same chemical properties. 
ANEK [815]3 years ago
5 0
A  they all exist as gases at 20c
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Lead can be extremely poisonous and was once used in many many paints but caused several deaths from lead poisoning so that was a biggie...
At the center of every chlorophyll molecule, in every plant, there is a magnesium ion. Magnesium is one of the two dozen or so elements that are <em>required </em>for life. 
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How many grams are in 6.50 moles of h2so4?
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You multiply 6.50 by the molar mass of H2SO4. 
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How are the number of protons represented in the periodic table?
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The atomic number represents the number of protons

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A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.
morpeh [17]

Answer:

              Final Temperature = 36.54 ⁰C

Explanation:

Lets suppose the gas is acting ideally, then according to Charle's Law, "<em>The volume of a fixed mass of gas at constant pressure is directly proportional to the absolute temperature</em>". Mathematically for initial and final states the relation is as follow,

                                                V₁ / T₁  =  V₂ / T₂

Data Given;

                  V₁  =  32 L

                  T₁  =  10 °C = 283.15 K             ∴ K = °C + 273.15

                  V₂  =  35 L

                  T₂  =  ??

Solving equation for T₂,

                         T₂  =  V₂ × T₁  / V₁

Putting values,

                         T₂  =  (35 L × 283.15 K) ÷ 32 L

                         T₂  =  309.69 K     ∴ ( 36.54 °C )

Result:

           As the volume is increased from 32 L to 35 L, therefore, the temperature must have increased from 10 °C to 36.54 °C.

3 0
3 years ago
You might need:
nikitadnepr [17]

Answer:

Mass = 14.3 g

Explanation:

Given data:

Mass of Mg(OH)₂  = 16.0 g

Mass of HCl = 11.0 g

Mass of MgCl₂ = ?

Solution:

Chemical equation:

Mg(OH)₂ + 2HCl    →   MgCl₂ + 2H₂O

Number of moles of Mg(OH)₂ :

Number of moles = mass/ molar mass

Number of moles = 16.0 g/ 58.3 g/mol

Number of moles = 0.274 mol

Number of moles of HCl :

Number of moles = mass/ molar mass

Number of moles = 11.0 g/ 36.5 g/mol

Number of moles = 0.301 mol

Now we will compare the moles of Mg(OH)₂  and HCl with MgCl₂.

                           Mg(OH)₂          :           MgCl₂

                                 1                 :               1

                                 0.274        :          0.274

                               HCl             :              MgCl₂

                                  2              :               1

                                0.301         :           1/2×0.301 = 0.150

The  number of moles of MgCl₂ produced by HCl are less so it will limiting reactant.

Mass of MgCl₂:

Mass = number of moles × molar mass

Mass = 0.150 ×  95 g/mol

Mass = 14.3 g

8 0
2 years ago
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