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Bumek [7]
3 years ago
6

Why are the elements fluorine (F) , chlorine (Cl) , and bromine (Br) all found in the same group within the periodic table? A) T

hey all exist as gases at 20°C) . B) They all react with the noble gases. C) They have the same chemical properties. D) They are all non-metals that form 1+ ions.
Chemistry
2 answers:
Sergio039 [100]3 years ago
6 0
Fluorine, Chlorine, Bromine, Iodine and Astatine are representing the family of elements called : halogens.
Halogens:
- all have 7 electrons in their outer shell,
- are very reactive elements,
- form - 1 ions.
Answer: C ) They have same chemical properties. 
ANEK [815]3 years ago
5 0
A  they all exist as gases at 20c
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Which acid-base buffer is most crucial to maintaining homeostasis within the human body?
Igoryamba

it is a i believe: Bicarbonate and carbonic acid (A)

3 0
3 years ago
Read 2 more answers
How many molecules are in 1.28 mols of silicon dioxide​
coldgirl [10]

Answer:

7.71x10^23 molecules

Explanation:

Avogadro's # = 6.022x10^23

1.28 mol SiO2 x 6.022x10^23/ 1 mol SiO2 = 7.71x10^23 molecules

8 0
2 years ago
An aqueous solution of methanol (MM = 32.04 g/mol) has a molality of 8.83 m and a density of 1.15 g/mL. What is the molarity of
hodyreva [135]

We have that the  the molarity of methanol in the solution is mathematically given as

Morality=7.91mol/l

<h3>Chemical Reaction</h3>

Question Parameters:

An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)

A molality of 8.83 m and a density of 1.15 g/mL.

Generally the equation for the   is mathematically given as

Morality=\frac{moles of solute }{mass of the solvent}

where

Mass of solution=(100+282.2)

Mass of solution=1289.9

Volume=1289.9/1.15

Volume=1.115L

Therefore

Morality=\frac{moles of solute }{mass of the solvent}

Morality=8.83/1.115

Morality=7.91mol/l

For more information on Chemical Reactionvisit

brainly.com/question/11231920

7 0
2 years ago
A sample of hydrogen gas at a pressure of 0.520 atm and a temperature of 26.2°C, occupies a volume of 15.4 liters. If the gas is
Oksanka [162]

Answer:

1.99 atm

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial pressure (P1) = 0.520 atm

Initial temperature (T1) = 26.2°C

Initial volume (V1) = 15.4L

Final temperature (T2) = constant = 26.2°C

Final volume (V2) = 4.02L

Final pressure (P2) =..?

Step 2:

Determination of the new pressure of the gas.

Since the temperature of the gas is constant, it means the gas is obeying Boyle's law. Thus, the new pressure of the gas can be obtained by applying the Boyle's law equation as shown below:

P1V1 = P2V2

0.520 x 15.4 = P2 x 4.02

Divide both side by 4.02

P2 = (0.520 x 15.4) / 4.02

P2 = 1.99 atm

Therefore, the new pressure of the gas is 1.99 atm

4 0
3 years ago
A 2.00L flask was filled with 4.00 mol of HI at a certain temperature and given sufficient time to react. At equilibrium the con
inn [45]

Answer:

The equilibrium concentration of I₂ is 0.400 M  and HI is 1.20 M, the Keq will be 0.112.

Explanation:

Based on the given information, the equilibrium reaction will be,  

2HI (g) ⇔ H₂ (g) + I₂ (g)

It is given that 4.00 mol of HI was filled in a flask of 2.00 L, thus, the concentration of HI will be,  

= 4.00 mol/2.00 L

= 2.00 mol/L

Based on the reaction, the initial concentration of 2HI is 2.00, H₂ is 0 and I₂ is O. The change in the concentration of 2HI is -x, H₂ is x and I₂ is x. The equilibrium concentration of 2HI will be 0.200-x, H₂ is x and I₂ is x.  

It is given that at equilibrium, the concentration of H₂ or x is 0.400 M.  

Now the equilibrium concentration of HI will be,  

= 2.00 -2x  

= 2.00 - 2 × 0.400

= 1.20 M

The equilibrium concentration of I₂ will be,  

I₂ = x  

= 0.400 M

The equilibrium constant (Keq) will be,  

Keq = [H₂] [I₂] / [HI]²

= (0.400) (0.400) / (1.20)²

= 0.112

Thus, the Keq of the reaction will be 0.112.  

5 0
3 years ago
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