Answer:
1mole of Argon contains 6.022x10^23atoms
3moles will contain
3x6.022x10^23atoms
1 atoms of Argon contains 18electrons
3x6.022x10^23atoms will contain...
3x6.022x10^23 x 18electrons
= 3.252x10^25electrons
Note:In a Neutral Argon... No of Electrons and Protons(positive charge) are the same
From Charge Quantization Principle
Q=ne
n=3.252x10^25protons
e=1.6x10^-19C
Q=3.252x10^25 x 1.6x10^-19
Q=5.2x10^6C
Answer:
Using the log combination rules to reduce the famous Sakur-Tetrode equation, The change in entropy is given as:
∆S = NK*ln(V"V$/V").
Where V"V$ is final Volume (Vf) after constraint's removal,
V" is Initial Volume (Vi) before constraint's removal.
Temperature (T) is constant, Internal Energy, U is constant, N and K have their usual notations
Explanation:
Given in the question, the container is an adiabatic container.
For an adiabatic contain, it does not permit heat to the environment due to its stiff walls. This implies that the Internal Energy, U is kept constant(Q = U). The temperature is also constant (Isothermal). Thus, the famous Sakur-Tetrode equation will reduce to ∆S = NK* In(Vf/Vi).
Vf is the volume after the constraint is removed(Vf = V"V$). Vi is the volume occupied before the constraint is removed (Vi = V")
Answer:
240
Explanation:
We know that Y is 800m from X, and located 400m north of X.
That means the cosine of the bearing of Y from X is 400m/800m = 1/2
We should remember (or use a calculator with arccos) that the angle for which the cosine is 1/2 is 60deg.
The bearing of Y from X is 060.
To get the bearing of X from Y, we just need to add or subtract 180 and we arrive at the answer - 240
Speed is the rate of change <span>of distance.</span>
Answer:
One of the indirect proofs that orbits change is actually in the growth of our own teeth when we were children. our teeth are some of the most basic, and primitive
parts of our bodies. They grow on a 9 day cycle, which was an ancient full moon to full moon cycle when the Earth and the Moon were a lot smaller, and closer together, and the co-orbital period was only 9 days, not the 29.5 days that it is currently.
So Given any two " Planets " that co-orbit a common gravitational center, the larger planet will grow larger far faster than the smaller planet, and the larger planet will accelerate the smaller planet to a higher orbit with a longer period, and decelerate itself to a lower orbit with a longer period, and the absolute value of the center to center distance will increase, and the orbital period will increase. The two orbs and their common gravitational center will remain co-linear through out the gradual growing and changing process.
This is an important process for the enlargement of the solar system as time passes, and an important process for larger galaxies as they attract and merge with smaller galaxies.
All of the planets grow larger at an accelerating rate, and thus systems spiral outward concentrating mass into larger and fewer galaxies, solar systems, and planet - moon systems.