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Vsevolod [243]
3 years ago
9

If all of the electron groups around a single central atom are bonding, and the same outer atom is bonded to the central atom in

each case, is the molecule polar, nonpolar, or does it depend on the identity of the outer atom?
Chemistry
1 answer:
daser333 [38]3 years ago
8 0

Answer:

It depends on the identity of the outer atom

Explanation:

We must recall that the polarity of a molecule depends on difference In electronegativity between atoms as well as the shape of the molecule.

When a central atom has no lone pairs and all the groups in the molecule are bonding, the identity and arrangement  of the outer atoms will determine the polarity of the molecule.

A polar molecule is formed by certain types of outer atoms arranged in  certain ways around the periodic table and vice versa.

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When 20.0 g of KI are dissolved in 50.0 mL of distilled water in a calorimeter, the temperature drops from 24.0 °C to 19.0 °C. C
Reil [10]
<h2>Answer:</h2>

<em>8.67kJ/mol</em>

<h2>Explanations</h2>

The formula for calculating the amount of heat absorbed by the water is given as:

\begin{gathered} q=mc\triangle t \\ q=50\times4.18\frac{J}{g^oC}\times(19-24) \\ q=50\times4.18\times(-5) \\ q=-1045Joules \\ q=-1.045kJ \end{gathered}

Determine the moles of KI

\begin{gathered} moles\text{ of KI}=\frac{mass\text{ of KI}}{molar\text{ mass of KI}} \\ moles\text{ of KI}=\frac{20g}{166g\text{/mol}} \\ moles\text{ of KI}=0.1205moles \end{gathered}

Since heat is lost, hence the enthalpy change of the solution will be negative that is:

\begin{gathered} \triangle H=-q \\ \triangle H=-(-1.045kJ) \\ \triangle H=1.045kJ \end{gathered}

Determine the enthalpy of solution in kJ•mol-1

\begin{gathered} \triangle H_{diss}=\frac{1.045kJ}{0.1205mole} \\ \triangle H_{diss}\approx8.67kJmol^{-1} \end{gathered}

Hence the enthalpy of solution in kJ•mol-1 for KI is 8.67kJ/mol

4 0
1 year ago
When you hammer a nail, which types of energy are you using? Select all of the correct answers.
zhuklara [117]

Answer:

U using kinetic energy

6 0
3 years ago
An 18 liter container holds 16.00 grams of oxygen gas (o2 at 45 °c. what is the pressure in the container?
Scrat [10]
Hello!

The pressure of an 18 L container which holds 16,00 grams of oxygen gas (O₂) at 45 °C is 0,725 atm

To solve this problem we first need to set up the data in the appropriate units to input it in the Ideal Gas Law.

a) 16 g of Oxygen gas to moles of oxygen gas:

16gO_2* \frac{1 mol O_2}{32gO_2}=0,5 mol O_2

b) 45 °C to K

K=$^{\circ}$C + 273,15 = 45 $^{\circ}$C + 273.15=318,15 K

Now, we clear the Ideal Gas Equation for P, and solve it:

P*V=n*R*T \\ \\ P= \frac{n*R*T}{V}= \frac{(0,5mol)*(0,082 \frac{L*atm}{mol*K})* (318,15 K)}{18 L}= 0,725 atm

Have a nice day!
4 0
3 years ago
Why do elements in the same colum have similar properties?
den301095 [7]

Answer:because they have the same number of valence electrons

Explanation:

Valence electrons determine reactivity.

6 0
3 years ago
Convert 345 g to kg<br> Determine the conversion factor and the answer<br> (1,000 g = 1 kg)
Musya8 [376]

Answer:

345000 grams

Explanation:

1000g = 1kg

6 0
3 years ago
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