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8090 [49]
2 years ago
15

If the volume of 1.00 mole of gas is tripled, what will happen to the pressure, if the temperature remains constant

Chemistry
1 answer:
Julli [10]2 years ago
8 0

Answer:

The new pressure becomes one third of the initial pressure.

Explanation:

The relation between pressure and volume at constant temperature is given by :

P\propto \dfrac{1}{V}\\\\P=\dfrac{1}{V}

Let new pressure and volume be P' and V' respectively.

V'=3V (given)

So,

P'=\dfrac{1}{V'}\\\\=\dfrac{1}{3V}\\\\=\dfrac{1}{3}\times \dfrac{1}{V}\\\\P'=\dfrac{1}{3}\times P

Hence, new pressure becomes one third of the initial pressure.

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0.0075 mole of calcium trioxocarbonate(IV) is
KatRina [158]

Answer:

0.0075÷0.015=0.5 not so sure lol

4 0
3 years ago
A balloon, whose volume at 23°C is 535 mL, is heated to 46°C. Assuming the pressure and amount of gas remain constant, what is t
NikAS [45]
This problem requires a certain equation.  That equation is V1/T1=V2/T2, where V1 is your initial volume (535 mL in this case), T1 is your initial temperature in Kelvin(23 degrees C = 296 K), V2 is your final volume (unknown), and T2 is your final temperature (46 degrees C = 319 K). By plugging in these values, the equation looks like this: 535/296=V2/319.  Now multiply both sides of the equation by 319, and your final answer is V2= 576.6 mL
5 0
3 years ago
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How much heat is needed to raise the temperature of 55.0 g sample of water by 65.0 oC.
sveticcg [70]

Answer: 14943.5 J

Explanation:

The quantity of heat energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that,

Q = ?

Mass of water = 55.0g

C = 4.18 J/g°C

Φ = 65.0°C

Then, Q = MCΦ

Q = 55.0g x 4.18 J/g°C x 65.0°C

Q = 14943.5 J

Thus, 14943.5 joules of heat is needed to raise the temperature of water.

3 0
3 years ago
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What is the balanced chemical equation for potassium and chlorine which form potassium chloride
ArbitrLikvidat [17]

Potassium metal + Chlorine Gas --------> Potassium Chloride<span>
The chemical equation using symbols and formula is
<span>K (s) + </span></span><span><span><span><span>Cl</span>2</span> </span><span>(g) ---------> 2KCl (s)</span></span>

3 0
3 years ago
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How many milliliters of 0.200 m fecl3 are needed to react with an excess of na2s to produce 1.38 g of fe2s3 if the percent yield
ahrayia [7]
<span>Answer: 100 ml
</span>

<span>Explanation:


1) Convert 1.38 g of Fe₂S₃ into number of moles, n


</span>i) Formula: n = mass in grass / molar mass
<span>
ii) molar mass of </span><span>Fe₂S₃ =2 x 55.8 g/mol + 3 x 32.1 g/mol = 207.9 g/mol
</span>

iii) n = 1.38 g / 207.9 g/mol = 0.00664 moles of <span>Fe₂S₃
</span>

<span>2) Use the percent yield to calculate the theoretical amount:
</span>

<span>65% = 0.65 = actual yield/ theoretical yield =>


</span>theoretical yield = actual yield / 0.65 = 0.00664 moles / 0.65 = 0.010 mol <span>Fe₂S₃</span><span>

3) Chemical equation:
</span>

<span> 3 Na₂S(aq) + 2 FeCl₃(aq) → Fe₂S₃(s) + 6 NaCl(aq)


4) Stoichiometrical mole ratios:
</span>

<span>3 mol Na₂S : 2 mol FeCl₃ : 1 mol Fe₂S₃ : 6 mol NaCl


5) Proportionality:


</span>2moles FeCl₃ / 1 mol Fe₂S₃ = x / 0.010 mol Fe₂S₃
<span>
=> x = 0.020 mol FeCl₃


6) convert 0.020 mol to volume
</span>

<span>i) Molarity formula: M = n / V
</span>

<span>ii) V = n / M = 0.020 mol / 0.2 M = 0.1 liter = 100 ml
</span>

3 0
3 years ago
Read 2 more answers
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