Ask question

Ask question

All categories

harkovskaia [24]

4 years ago

12

Which element is likely to gain one electron when it combines chemically with another element? a potassium b krypton c gold d ch

lorine?

1 answer:

11Alexandr11 [23.1K]4 years ago

7 0

Chlorine because it lacks one valence electron to fill it's outer shell

You might be interested in

If an element is more reactive, is it more likely to be found as an element or a compound?

laila [671]

It is more likely to be found as a COMPOUND, as it is more reactive, by the time we found them, they're already reacted with other elements or compounds to form new compounds.
Example is oxygen, it is very reactive, therefore we often found oxygen in water, which is H2O, in earth, instead of just pure oxygen.

5 0

3 years ago

Given: N2 + 3Cl2 → 2NCl3, ΔH = 464 kJ/mol Use the given bond energies and the periodic table to calculate the energy change in t

guapka [62]

The given chemical reaction is:

$N_{2}+3Cl_{2}-->2NCl_{3}$

Δ $H^{0}_{reaction}=$ ∑BE(reactants)-∑BE(products)

= {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]

= 467 kJ/mol

Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:

Moles of chlorine = $85.3 g Cl_{2}* \frac{1 mol Cl_{2}} {70.91 g Cl_{2} }$

= 1.20 mol $Cl_{2}$

Heat change when 1.20 mol chlorine reacts

= $1.20 mol * \frac{467kJ}{mol} =560.4 kJ$

6 0

3 years ago

I’m really behind in chemistry and my school is alpha and omega academy. If anyone could help me catch up or knows the answers p

victus00 [196]

Hxhjddjdjdjdjjdjdjdjdjdjdj

8 0

3 years ago

Electronic configuration for Cr, Cu, Cr+2, Cu+2, Mn+2

Zanzabum

Chromium (Cr): 2, 8, 8, 6
Copper (Cu): 2, 8, 8, 11
Chromium+2 (Cr+2): 2, 8, 8, 4 (if the ion retains a positive charge then the amount of electrons will decrease)
Copper+2 (Cu+2): 2, 8, 8, 9
Manganese+2 (Mn+2): 2, 8, 8, 5

8 0

4 years ago

Read 2 more answers

Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline.

lesya692 [45]

Answer:

$n_{CO_2}=1.93 gCO_2$

Explanation:

Hello,

In this case, considering the given chemical reaction, we can use the molar mass of octane (114.23 g/mol) and the 2:16 molar ratio with carbon dioxide to compute the emitted moles of CO2 to the atmosphere via the following stoichiometric procedure:

$n_{CO2}=27.6gC_8H_{18}*\frac{1molC_8H_{18}}{114.23gC_8H_{18}} *\frac{16molCO_2}{2molC_8H_{18}} \\\\n_{CO_2}=1.93 gCO_2$

Which also corresponds to the following mass:

$m_{CO_2}=1.93molCO_2*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=85.0gCO_2$

Best regards.

6 0

3 years ago