Answer:
10628.87 J
Explanation:
We are given that
Force applied =F=5592 N
![\theta=30.1^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D30.1%5E%7B%5Ccirc%7D)
Displacement=D=3.79 m
We have to find the work done in sliding the piano up the plank at a slow constant rate.
Work done=![F\times displacement](https://tex.z-dn.net/?f=F%5Ctimes%20displacement)
The perpendicular component of force=![FSin\theta=5592sin(30.1)=2804.45N](https://tex.z-dn.net/?f=FSin%5Ctheta%3D5592sin%2830.1%29%3D2804.45N)
Work done =![Fsin\theta\times D=2804.45\times 3.79=10628.87 J](https://tex.z-dn.net/?f=Fsin%5Ctheta%5Ctimes%20D%3D2804.45%5Ctimes%203.79%3D10628.87%20J)
Hence, the work done in sliding the piano up the plank at a slow constant rate=10628.87 J
Answer:
D) A warm front brings drizzly weather.
Explanation:
0.29 m/s (wave velocity = wavelength (lamda)/period (T) in metres)
35 / 1.2 = 29.16
29.16 ÷ 100 = 0.29
Wave velocity in string:
The properties of the medium affect the wave's velocity in a string. For instance, if a thin guitar string is vibrated while a thick rope is not, the guitar string's waves will move more quickly. As a result, the linear densities of the two strings affect the string's velocity. Linear density is defined as the mass per unit length.
Instead of the sinusoidal wave, a single symmetrical pulse is taken into consideration in order to comprehend how the linear mass density and tension will affect the wave's speed on the string.
Learn more about density here:
brainly.com/question/15164682
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Answer:
Explanation:
The momentum of the 25 kg mass is
![p=mv](https://tex.z-dn.net/?f=p%3Dmv)
![p=25kg*3m/s= 75kg*m/s](https://tex.z-dn.net/?f=p%3D25kg%2A3m%2Fs%3D%2075kg%2Am%2Fs)
If this whole momentum of the object is transferred to the 5.0 kg object then according to the law of conservation of momentum, the momentum of the 25.0 kg object must be transferred to the 5.0 kg object:
![75kg*m/s = 5.0kg*v](https://tex.z-dn.net/?f=75kg%2Am%2Fs%20%3D%205.0kg%2Av)
![v=\dfrac{75}{5}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B75%7D%7B5%7D)
![\boxed{v=15m/s}](https://tex.z-dn.net/?f=%5Cboxed%7Bv%3D15m%2Fs%7D)