Answer: the constant angular velocity of the arms is 86.1883 rad/sec
Explanation:
First we calculate the linear velocity of the single sprinkler;
Area of the nozzle = π/4 × d²
given that d = 8mm = 8 × 10⁻³
Area of the nozzle = π/4 × (8 × 10⁻³)²
A = 5.024 × 10⁻⁵ m²
Now total discharge is dived into 4 jets so discharge for single jet will be;
Q_single = Q / n = 0.006 / 4 = 1.5 × 10⁻³ m³/sec
So using continuity equation ;
Q_single = A × V_single
V_single = Q_single/A
we substitute
V_single = (1.5 × 10⁻³) / (5.024 × 10⁻⁵)
V_single = 29.8566 m/s
Now resolving the forces as shown in the second image,
Vt = Vcos30°
Vt = 29.8566 × cos30°
Vt = 25.8565 m/s
Finally we calculate the angular velocity;
Vt = rω
ω_single = Vt / r
from the given diagram, radius is 300mm = 0.3m
so we substitute
ω_single = 25.8565 / 0.3
ω_single = 86.1883 rad/sec
Therefore the constant angular velocity of the arms is 86.1883 rad/sec
Explanation:
Given data
The elevator mass=3.0×10³ kg
Time t=23 s
elevator lift d=210 m
The power is the average rate of work done:
So
P=F.V Cosα
Where F is force
V is velocity
α is angle between Force and velocity
Apply the Newton Law to find the force on elevator
The velocity of elevator is given as
Since the net force has same direction of motion so α=0°
So
Answer: 1.2 seconds
Explanation:
Initial velocity =u=13.9m/s
Acceleration due to gravity=g=9.8m/s^2
Φ=25°
Time=t
T=(2 x u x sinΦ) ➗ g
T=(2 x 13.9 x sin25) ➗ 9.8
T=(2 x 13.9 x 0.4226) ➗ 9.8
T=11.75 ➗ 9.8
T=1.2 seconds
Answer:
Part a)
Part b)
Part c)
Explanation:
As per Newton's II law we know that
F = ma
so we will have
so we will have
Part a)
Part b)
Part c)
The force the cannonball is exerting on the moon, or the weight of the cannonball, is 32 Newtons because the formula used to calculate force is
, the Mass being 20 Kilograms and the Acceleration being 1.6 meters per second^2