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Angelina_Jolie [31]
3 years ago
12

What do the iron filings around this magnet show?

Physics
1 answer:
Anarel [89]3 years ago
6 0

Answer:

the opposite connections of the poles

Explanation:

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Explain the difference between speed and velocity and indicate if these are scalar or vector quantities
Natali5045456 [20]
Speed can never be negative because it does not depend in which direction the car moves whereas, velocity will change if a car turns from due North to East.
Quantities which can be described only by their magnitudes are called scalars and those which are described by both, magnitude and direction are vectors
3 0
3 years ago
A 1 900-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 4.00 m before coming into contact
Leno4ka [110]

Answer:

471392.4 N

Explanation:

From the question,

Just before contact with the beam,

mgh = Fd.................... Equation 1

Where m = mass of the beam, g = acceleration due to gravity, h = height. F =  average Force on the beam, d = distance.

make f the subject of the equation

F = mgh/d................ Equation 2

Given: m = 1900 kg, h = 4 m, d = 15.8 = 0.158 m

Constant: g = 9.8 m/s²

Substitute into equation 2

F = 1900(4)(9.8)/0.158

F = 471392.4 N

6 0
3 years ago
When beryllium-7 ions (m = 11.65 × 10-27 kg) pass through a mass spectrometer, a uniform magnetic field of 0.205 T curves their
AysviL [449]

Answer:

ratio =0.3075 T

Explanation:

The magnetic field B creates a force on a moving charge such that

F = qvB

Now this causes a centripetal acceleration

F =  = mv^2/r

 so

qvB = mv^2/r ...........(i)

B = mv/(rq)  ...............(ii)

If  accelerating potential V is  same and  then  kinetic energy equals the potential energy difference

\frac{1}{2} mv^2 = Vq

v = \sqrt{(2Vq/m)}      put these value in equation (ii)

B = m\frac{\sqrt{(2Vq/m)} }{rq}  

simplifying we get  

B =m \frac{(\sqrt{ 2Vm/q})}{r}

for same location r will be same in both case

B_{7} = \frac{ \sqrt{(m_{7})(2V/q) }}{r}      ..............(iii)

B_{10} = \frac{ \sqrt{(m_{10})(2V/q) }}{r}    ..........(iv)

 dividing (iv) and (iii) equation we get

\frac{B_{10}}{B_{7}}   =   \sqrt{\frac{m_{10}}{{m_7}} }

{B_{10}}  =  B_{7}  \sqrt{\frac{m_{10}}{{m_7}} }

B_{10}       = 0.2574T\sqrt{\frac{  (1.663x10^-26}{(1.165x10^-26)}

so on solving we get  

             =0.3075 T

5 0
3 years ago
Which star has the highest surface temperature?
Furkat [3]
The blue star is the hottest star.

Fun Fact: The coldest stars are red
4 0
4 years ago
provides one model for solving this problem. The maximum strength of the earth's magnetic field is about 6.9 x 10-5 T near the s
jeka57 [31]

Answer:

The minimum no. of turns is 3.126 \times 10^{5}

Explanation:

Given:

Magnetic field B = 6.9 \times 10^{-5} T

Frequency f = 84.5 Hz

Area of turn A = 0.021 m^{2}

Voltage V_{rms}  = 170 V

From the formula of induced emf,

V = NBA \omega

Where \omega = 2\pi f and V = \sqrt{2} V_{rms}

So number of turn is,

N = \frac{\sqrt{2} V_{rms} }{AB2\pi f }

N = \frac{\sqrt{2} \times 170 }{0.021 \times 6.9 \times 10^{-5} \times 6.28 \times 84.5 }

N = 3.126 \times 10^{5}

Therefore, the minimum no. of turns is 3.126 \times 10^{5}

4 0
3 years ago
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