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N76 [4]
3 years ago
5

What is the converse of the statement given? "If a triangle is equilateral, then it is isosceles." Question 1 options: A triangl

e is equilateral if and only if it is isosceles. A triangle is not isosceles then if it is not equilateral. If a triangle is isosceles, then it is equilateral. All equilateral triangles are isosceles.
Mathematics
1 answer:
iVinArrow [24]3 years ago
7 0
The converse of a mathematical statement involves simply switching the hypothesis and the conclusion, thus:
"If a triangle is isosceles, then it is equilateral."
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Find the mean of the first 7 odd prime number?​
bekas [8.4K]

Answer: 75/7 or 10.71 (rounded)

Step-by-step explanation:

Mean = Average

To find the average you should add all the numbers together and then divide it by the amount of numbers.

In this question, the formula is \frac{n_1+n_2+n_3+n_4+n_5+n_6+n_7}{7}

----------------------------------------------------------------------------------------

The list of the first 7 odd prime numbers:

3, 5, 7, 11, 13, 17, 19

Now, add them together

3+5+7+11+13+17+19=75

Divide the sum by 7

75÷7=75/7=10.71 (rounded)

Hope this helps!! :)

Please let me know if you have any questions

6 0
3 years ago
Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6
Ivan

Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

y = \dfrac{1}{6}(x - 8)^2 + 6

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

\text{focus} = (h, k +\frac{1}{4a})

where \frac{1}{4a} is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}

By definition, the length of the latus rectum is four times the focal length so therefore, its value is

\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6

5 0
3 years ago
Can someone help me out with this problem
ohaa [14]

Answer:

\fbox {1) A}\\\fbox {2) A}

Step-by-step explanation:

<u>Q1</u>

⇒ Graph A is most accurate as the situation is linear and the dots indicate per cup as you can't have any rational part (such as 0.5 cups, etc.)

<u>Q2</u>

⇒ A

⇒ The graph is discrete because the sellers have limited the purchaser to buy a distinct whole number of cups

3 0
2 years ago
Drag each set of column entries to the correct location in the matrix equation. Not all sets of entries will be used. A biker ne
ANEK [815]

Answer:

The matrix equation is \left[\begin{array}{ccc}1&1&1\\1&-1/2&0\\0&2&-1\end{array}\right]=\left[\begin{array}{c}120&35&20\end{array}\right]

Step-by-step explanation:

* Lets change the story problem to equations

- The distance between the starting point and checkpoint 1 is x

- The distance between checkpoint 1 to checkpoint 2 is y

- The distance between checkpoint and the finish line is z

- The total distance for the race is 120 miles

∴ x + y + z = 120 ⇒ (1)

-The distance from the starting point to checkpoint 1 is 35 miles

 more than half the distance from checkpoint 1 to checkpoint 2

∵ The distance from the starting point to checkpoint 1 is x

∵ The distance from checkpoint 1 to checkpoint 2 is y

- x is more than half y by 35

∴ x = 35 + (1/2) y ⇒ subtract (1/2) y from both sides

∴ x - (1/2) y = 35 ⇒ (2)

- The distance from checkpoint 2 to the finish line is 20 miles less

 than twice the distance from checkpoint 1 to checkpoint 2

∵ The distance from checkpoint 2 to the finish line is z

∵ the distance from checkpoint 1 to checkpoint 2 is y

- z is less than twice y by 20

∴ z = 2y - 20 ⇒ add 20 to both sides

∴ z + 20 = 2y ⇒ subtract z from both sides

∴ 2y - z = 20 ⇒ (3)

* Now lets write the three equations

# x + y + z = 120 ⇒ (1)

# x - (1/2) y = 35 ⇒ (2)

# 2y - z = 20 ⇒ (3)

- Now lets write the matrix equation that models this situation

∴ \left[\begin{array}{ccc}1&1&1\\1&-1/2&0\\0&2&-1\end{array}\right]=\left[\begin{array}{c}120&35&20\end{array}\right]

6 0
3 years ago
Read 2 more answers
5 positive integers are arranged in ascending order, as follows:
Helga [31]
The answer is: 10.

Explanation: The numbers are in order by the median/lowest to highest so in that case X wouldn't be 7 because the X would have been next to the 7 not on the other side of the 10.
4 0
2 years ago
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