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mixer [17]
3 years ago
10

A car that is traveling in a straight line at 40 km/h can brake to a stop within 20 m. If the same car is traveling at 120 km/h

what would be its stopping distance in this case? Assume the braking force is the same in both cases and ignore air resistance.
Physics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

180 m

Explanation:

Case 1.

U = 40 km/h = 11.1 m/s, V = 0, s = 20 m

Let a be the acceleration.

Use third equation of motion

V^2 = u^2 + 2 as

0 = 11.1 × 11.1 - 2 × a × 20

a = 3.08 m/s^2

Case 2.

U = 220 km/h = 33.3 m/s, V = 0

a = 3.08 m/s^2

Let the stopping distance be x.

Again use third equation of motion

0 = 33.3 × 33.3 - 2 × 3.08 × x

X = 180 m

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¿Qué resistencia debe ser conectada en paralelo con una de 20 Ω para hacer una
ValentinkaMS [17]

Answer:

60 Ω

Explanation:

R(com) = 15 Ω

1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn

1/15 = 1/20 + 1/R2

1/R2 = 1/15 - 1/20

1/R2 = (4 - 3) / 60

1/R2 = 1/60

R2 = 60 Ω

así, la combinada de resistencia necesaria es 60 Ω

5 0
3 years ago
how much time would it take for the sound of thunder to travel 1,500 meters if sound travels at a speed of 330m/s
user100 [1]

Answer:

4.545454 seconds

Explanation:

1500/330=4.545454 seconds

5 0
3 years ago
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Hurricanes are powered by heat energy in the atmosphere and the ocean. Typically, one hurricane uses an amount of heat roughly e
lesya692 [45]

Answer:

In an year about 6 major hurricanes and 3 minor storms occurs.

Explanation:

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3 0
2 years ago
A cannon fires a cannonball of mass 16.0 kg by applying a force of 2750 N along the 1.25 m length of the barrel. (a) How much wo
Zarrin [17]

To develop this problem it is necessary to apply the concepts related to Work and energy conservation.

By definition we know that the work done by a particle is subject to the force and distance traveled. That is to say,

W = F*d

Where,

F= Force

d = Distance

On the other hand we know that the potential energy of a body is given based on height and weight, that is

PE = -mgh

The total work done would be given by the conservation and sum of these energies, that is to say

W_{net} = W+PE

PART A) Applying the work formula,

W = F*d\\W = 2750*1.25\\W = 3437.5J

PART B) Applying the height equation and considering that there is an angle in the distance of 25 degrees and the component we are interested in is the vertical, then

PE = -mgh*sin25

PE = -16*9.81*1.15sin25

PE = -82.9J

The net work would then be given by

W_{net} = W+PE

W_{net} = 3437.5J-82.9J

W_{net} = 3354.6J

Therefore the net work done by these 2 forces on the cannonball while it is in the cannon barrel is 3355J

3 0
3 years ago
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Luba_88 [7]

Answer:

c is correct

Explanation:

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Which of the following terms BEST describes steel? homogeneous mixture

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3 years ago
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