Answer:
Q = 797.5 cal
Explanation:
Given that,
Mass of iron, m = 50 g
The temperature rises from 55°C to 200°C.
We need to find the heat needed to raise the temperature. The heat raised is given by :

Put all the values,

So, 797.5 calories of heat is needed.
Yes , the chemist can answer if the compound in K2O or K2O2
The chemical formula and composition of both the compounds is entirely different. The compound K2O2 has an additional molecule of oxygen than K2O and hence will have have higher molecular mass.
In the compound K2O
molecular mass= 2x 39+16 =94
mass ratio of K in compound= 78/94 = 0.830
In the compound K2O2
molecular mass= 2x 39+16X2 =110
mass ratio of K in compound= 78/110 = 0.710
and hence by the required ratio while extracting K , the chemist may know if the compound is K20 or K2O2
If the ratio is anything different from 0.830 and 0.710 then the compund will be something different
#SPJ9
Answer: 1.72cm
Explanation:
First let us calculate the mass of titanium that contain 2.86×10^23 atoms..
1mole of a substance contains 6.02x10^23 atoms as we have come to understand from Avogadro's hypothesis. Therefore, 1mole of titanium also contains 6.02x10^23 atoms.
1mole of titanium = 48g
1mole (i.e 48g) of titanium contains 6.02x10^23 atoms,
Therefore Xg of titanium will contain 2.86×10^23 atoms i.e
Xg of titanium = (48x2.86×10^23)/6.02x10^23 = 22.8g
Next, we must find the volume of titanium
Density of titanium = 4.5g/cm^3
Mass of titanium = 22.8g
Volume =?
Density = Mass /volume
Volume = Mass /Density
Volume = 22.8/4.5
Volume = 5.07cm^3
Now we can find the edge length:
Volume = 5.07cm^3
Length =?
V = L^3
L = cube root (V)
L = cube root (5.07)
L = 1.72cm
Answer:

Explanation:
Hello,
In this case, since the volume is computed by multiplying the given dimensions as follows:

The result is shown in cubic meters since each meter is also added:

Best regards.
Answer: The concentration of hydrogen ion is 2.5 x 10∧-3.
Explanation:
It is well known that; pH + pOH = 14
∴ pH + 11.40 = 14
pH = 14 -11.40 = 2.60
Remember that,
pH = - Log [ H+ ]
2.60 = - log [H+]
To get the hydrogen ion concentration, we take the anti-log of 2.60.
[H+] = Antilog 2.60 = 2.5 x 10∧-3.