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laila [671]
3 years ago
11

In a particular area of the country, electrical energy costs $0.12 per kilowatt-hour. (Round your answers, in dollars, to at lea

st two decimal places.) (a) How much does it cost to operate an old-style incandescent 100-W light bulb continuously for 24 hours? $ (b) A modern LED light bulb that emits as much visible light as a 100-W incandescent only draws 16.0 W of power. How much does it cost to operate this bulb for 24 hours? $ (c) A particular electric oven requires a potential difference of 220 V and draws 20.0 A of current when operating. How much does it cost to operate the oven for 5.30 hours? $
Physics
1 answer:
Delvig [45]3 years ago
7 0

Answer:

a) cost = $ 0.29 , b) cost = $ 0.046 ,  c) cost = $ 2.80

Explanation:

a) Let's find the energy consumed by this bulb, which is the product of the power and time

         energy = P t

         energy = 100 24 = 2400 W h

as the cost of energy is given in kWh we reduce this value

         Energy = 2400 Wh (1 kW / 1000W)

         Energy = 2.40 kWh

Calculate the cost of energy

           cost = 0.12 2.40

           cost = $ 0.288

           cost = $ 0.29

 

b) energy = 16.0  24 = 384 Wh

we reduce to kWh

      energy = 0.384 kWh

      cost = 0.12 0.384

      cost = $ 0.0461

      cost = $ 0.046

c) let's find the power consumed by the oven

       P = I V

       P = 20.0 220

       P = 4400 W

we look for the energy consumed

       energy = 4400  5.30

       energy = 23320 Wh

we reduce to kWh

       energy = 23.32 kWh

we calculate the cost of this energy

       cost = 0.12 23.32

       cost = $ 2,798

       cost = $ 2.80

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A 14.0 m uniform ladder weighing 490 N rests against a frictionless wall. The ladder makes a 63.0°-angle with the horizontal.
crimeas [40]

Answer:

Explanation:

Given:

length of ladder r_L = 14m

weight of ladder F_L = 490N

position of firefighter r_F = 3.8m

weight of firefighter F_F = 820N

angle of ladder \alpha = 63

Unknown:

force of the wall on the ladder F_W

force of friction on base of ladder F_R

normal force on base of ladder F_N

From the free body diagram of the sketch you get 3 equations:

F_x = ma_x = F_W - F_R = 0\\ F_y = ma_y = F_N - F_F - F_L = 0\\ \tau _P = \overrightarrow{r} \times \overrightarrow{F} = r_FF_Fcos\alpha + \frac{1}{2}r_LF_Lcos\alpha - r_LF_Wsin\alpha = 0

Solving the equations gives:

F_W = F_R\\ F_N = F_F + F_L\\ F_W = \frac{r_FF_F + 0.5r_LF_L}{r_L tan\alpha}

a)

F_R = 238N\\ F_N = 1310N

b)

F_R = \mu F_N\\ \mu = \frac{F_R}{F_N} \\ \mu = 0.3

c) Using the result from b and solving for r_F

\\ \mu = 0.15\\ F_R = \mu F_N\\ r_F = 2.4m

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Answer:

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What is the relationship between thickness of lens and focal length?​
Ymorist [56]

Thick lens will have shorter and consequently thin lens will have greater focal length. Because, For a thick lens, the optical path length of the light is more, than for a thin lens, thus, the bending of light will be more in case of a thicker lens. Consequently, it has a shorter focal length.

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2 years ago
A sled of mass 2.12 kg has an initial speed of 5.49 m/s across a horizontal surface. The coefficient of kinetic friction between
Darya [45]

Answer:

The speed of the sled is 3.56 m/s

Explanation:

Given that,

Mass = 2.12 kg

Initial speed = 5.49 m/s

Coefficient of kinetic friction = 0.229

Distance = 3.89 m

We need to calculate the acceleration of sled

Using formula of acceleration

a = \dfrac{F}{m}

Where, F = frictional force

m = mass

Put the value into the formula

a=\dfrac{\mu mg}{m}

a=\mu g

a=0.229\times9.8

a=2.244\ m/s^2

We need to calculate the speed of the sled

Using equation of motion

v^2=u^2-2as

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value in the equation

v ^2=(5.49)^2-2\times2.244\times3.89

v=\sqrt{(5.49)^2-2\times2.244\times3.89}

v=3.56\ m/s

Hence, The speed of the sled is 3.56 m/s.

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Water must absorb energy in order to melt, evaporate, or get warmer.

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