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Fed [463]
3 years ago
11

How does silicon dioxide become a covalent bond. (explain)

Chemistry
1 answer:
tatuchka [14]3 years ago
4 0
Silicon dioxide is SiO2.  Silicon has 4 valence electrons, while each oxygen has 6 valence electrons.  This can be shown as 
     **             *                   *
**  O *       *  Si   *        *   O  **
      *               *                 **
At points where there is one valence electron, represented by a lone *, the electrons will be 'shared' between the atoms.  This will make silicon dioxide appear as
   **           *--------------- *
**  O *--*  Si   * ------ *   O  **
      *------- *                 **
, as the lines with no arrows indicate that each electron moves between the atoms, and does not stay with one forever.
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Explanation:

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Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

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