Answer:
0.013%
Yes, it does. The answer agrees with the statement.
Explanation:
Both conformers are in equilibrium, and it can be represented by the equilibrium equation K:
K = [twist-boat]/[chair]
The free energy between them can be calculated by:
ΔG° = -RTlnK
Where R is the gas constant (8.314 J/mol.K), and T is the temperature (25°C + 273 = 298 K).
ΔG° = 5.3 kcal/mol * 4.182 kJ/kcal = 22.165 kJ/mol = 22165 J/mol
22165 = -8.314*298*lnK
-2477.572lnK = 22165
lnK = -8.946
K = 
K = 1.30x10⁻⁴
[twist-boat]/[chair] = 1.30x10⁻⁴
[twist-boat] = 1.30x10⁻⁴[chair]
The percentage of the twist-boat conformer is:
[twist-boat]/([twist-boat] + [chair]) * 100%
1.30x10⁻⁴[chair]/(1.30x10⁻⁴[chair] + [chair]) *100%
0.013%
The statement about the conformers is that the chair conformer is more stable, and because of that is more present. So, the answer agrees with it.
Answer:
0.95L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 1L
T1 (initial temperature) = 315K
P1 (initial pressure) = 1.10 atm
T2 (final temperature) = stp = 273K
P2 (final pressure) = stp = 1atm
V2 (final volume) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the system can be obtained as follow:
P1V1/T1 = P2V2/T2
1.1 x 1/315 = 1 x V2/273
Cross multiply to express in linear form.
315 x V2 = 1.1 x 273
Divide both side by 315
V2 = (1.1 x 273) /315
V2 = 0.95L
Therefore, the final volume of the system if STP conditions are established is 0.95L
Density, Volume and Mass
3. A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water
level rose to the 37.4 mL mark.
a) Calculate the density of the metal (in g/mL).
b) If you were to do this with an equal mass of aluminum (d = 2.7 g/mL), how high would the water rise?
Answer: option D
Explanation:
Since optical isomers are of 2 types called Enantiomers and Diastereomers
Enantiomers are non super impossible mirror images to each other. Examples, a man's right and left hand, Gloves
Diastereomers are non super impossible non mirror images
