All categories

2 years ago

2. Convert 340,000 to scientific notation

Chemistry

2 answers:

arlik [135]2 years ago

8 0

Answer:

3.4 x 10^5

Explanation:

ivann1987 [24]2 years ago

4 0

Answer:

3.4 x 10 ^5

Explanation:

You might be interested in

Determine the pH of a KOH solution made by mixing 0.251 g KOH with enough water to make 1.0 × 10 2 mL of solution

vesna_86 [32]

Answer:

pH = 12.65

Explanation:

From the given information:

number of moles =mass in gram / molar mass

number of moles of KOH = mass of KOH / molar mass of KOH

number of moles of KOH = 0.251 g / 56.1 g/mol = 0.004474 mol

For solution :

number of moles = Concentration × volume

concetration = number of moles/ volume

concetration = 0.004474 mol / 0.100 L

concetration = 0.04474 M

We know that 1 moles KOH result into 1 mole OH⁻ ions

Therefore, Molarity of OH⁻ = 0.04474 M

Now,

pOH = -log[OH⁻]

pOH = -log (0.04474) M

pOH = 1.35

Similarly,

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 1.35

pH = 12.65

6 0

2 years ago

Wastewater discharged into a stream by a sugar refinery contains 3.40 g of sucrose (C12H22O11) per liter. A government-industry

Ipatiy [6.2K]

Answer: The pressure that must be applied to the apparatus is 0.239 atm

Explanation:

To calculate the osmotic pressure, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

or,

$\pi=i\times \frac{m_{solute}}{M_{solute}\times V_{solution}\text{ (in L)}}}\times RT$

where,

$\pi$ = osmotic pressure of the solution

i = Van't hoff factor = 1 (for non-electrolytes)

$m_{solute}$ = mass of sucrose = 3.40 g

$M_{solute}$ = molar mass of sucrose = 342.3 g/mol

$V_{solution}$ = Volume of solution = 1 L

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $20^oC=[20+273]K=293K$

Putting values in above equation, we get:

$\pi =1\times \frac{3.40g}{342.3g/mol\times 1}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 293K\\\\\pi =0.239atm$

Hence, the pressure that must be applied to the apparatus is 0.239 atm

3 0

3 years ago

What is the concentration created when 380.0g of Pb(NO3)2 is added to 330.0 mL of solution?

Juliette [100K]

The concentration of lead nitrate is 3.48 M.

Explanation:

The molarity can be found by dividing moles of sucrose by its volume in litres. We can find the number of moles of sucrose by dividing the given mass by its molar mass. Now we can find the moles as,

Here mass of Pb(NO₃)₂ is 380 g

Molar mass of Pb(NO₃)₂ is 331.2 g/mol

Number of moles = $$\frac{given mass}{molar mass}$

= $$ \frac{380 g }{331.2 g/mol}$

= 1.15 moles

Volume in Litres = 330 ml = 0.33 L

Molarity = $$\frac{Moles}{Volume (L)}$

= 3.48 mol/L or 3.48 M

So the concentration of lead nitrate is 3.48 M.

7 0

2 years ago

Number 8!!!!! pls I don't get it

vlada-n [284]

I think the answer would be 1.58 g.

5 0

2 years ago

Is steel wool an element,compound,or mixture

4vir4ik [10]

Steel wool is neither, but it is mixture of iron with carbon.

5 0

2 years ago

Read 2 more answers