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nirvana33 [79]
3 years ago
15

____ are formed where bumps from two surfaces come into contact.

Physics
2 answers:
NemiM [27]3 years ago
6 0

the answer is Friction.

hope this heslp

olga_2 [115]3 years ago
4 0

Micro welds are formed where bumps from two surfaces come into contact.

<u>Explanation:</u>

The surface of all existing objects or elements, have some bumps and dips. Whenever the surfaces of two different bodies with bumps and dips come into contact with each other, sticking occur.

This causes the production of micro welds between the two surfaces that inhibit the smooth motion. These micro welds create a static force that opposes the smooth motion between the surfaces. This is called “friction”.

This friction force can be stopped only when it can either be dominated with the equal opposite force or inhibited with lubricating agents that reduce its effect on the surfaces of the two respective objects.

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If the body's temperature is above 105 °F for a prolonged period, heat stroke
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Answer:

A

Explanation:

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since the answers are spread apart, technically you can just estimate by doing -32

and then /2

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The difference in the composition of the terrestrial planets and the gas giants can be explained by the different condensation
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What rock type would most likely be found in the location marked by the black rectangle in the diagram below?
pychu [463]

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5 0
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Read 2 more answers
Can you describe how and why the molecules move from one side to the other?
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2 years ago
A 2.00-m long uniform beam has a mass of 4.00 kg. The beam rests on a fulcrum that is 1.20 m from its left end. In order for the
Shalnov [3]

Answer:

x ’= 1,735 m,  measured from the far left

Explanation:

For the system to be in equilibrium, the law of rotational equilibrium must be fulfilled.

Let's fix a reference system located at the point of rotation and that the anticlockwise rotations have been positive

             

They tell us that we have a mass (m1) on the left side and another mass (M2) on the right side,

the mass that is at the left end x = 1.2 m measured from the pivot point, the mass of the right side is at a distance x and the weight of the body that is located at the geometric center of the bar

           x_{cm} = 1.2 -1

          x_ {cm} = 0.2 m

          Σ τ = 0

          w₁ 1.2 + mg 0.2 - W₂ x = 0

          x = \frac{m_1 g\ 1.2 \ + m g \ 0.2}{M_2 g}

          x = \frac{m_1 \ 1.2 \ + m \ 0.2 }{M_2}

let's calculate

          x = \frac{2.9 \ 1.2 \ + 4 \ 0.2 }{8.00}2.9 1.2 + 4 0.2 / 8

           

          x = 0.535 m

measured from the pivot point

measured from the far left is

           x’= 1,2 + x

           x'=  1.2 + 0.535

           x ’= 1,735 m

8 0
3 years ago
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