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Liula [17]
3 years ago
13

What are the approximate solutions to the quadratic function x^2+6x-4=0

Engineering
1 answer:
posledela3 years ago
6 0
Solve the equation for
x
x
by finding
a
a
,
b
b
, and
c
c
of the quadratic then applying the quadratic formula.
Exact Form:
x
=
3
±
√
13
x
=
3
±
13
Decimal Form:
x
=
6.60555127
…
,
−
0.60555127
…
x
=
6.60555127
…
,
-
0.60555127
…
You might be interested in
The pressure of a gas in a rigid container is 125kpa at 300k, what we be the new pressure if the temperature increases to 900k​
kipiarov [429]

Answer:

375 KPa

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 125 KPa

Initial temperature (T₁) = 300 K

Final temperature (T₂) = 900 K

Final pressure (P₂) =?

The new (i.e final) pressure of the gas can be obtained as follow:

P₁/T₁ = P₂/T₂

125 / 300 = P₂ / 900

Cross multiply

300 × P₂ = 125 × 900

300 × P₂ = 112500

Divide both side by 300

P₂ = 112500 / 300

P₂ = 375 KPa

Thus, the new pressure of the gas is 375 KPa

7 0
3 years ago
Fill in the correct answer.
mestny [16]

Answer:

Explanation:

A conservator with a(n) guardianship background and knowledge of foreign languages will have more job opportunities because they broaden the scope of work a conservator can undertake.

6 0
3 years ago
1. (15) A truck scale is made of a platform and four compression force sensors, one at each corner of the platform. The sensor i
Elanso [62]

Answer:

a). 139498.24 kg

b). 281.85 ohm

c). 10.2 ohm

Explanation:

Given :

Diameter, d = 22 m

Linear strain, $\epsilon$ = 3%

                        = 0.03

Young's modulus, E = 30 GPa

Gauge factor, k = 6.9

Gauge resistance, R = 340 Ω

a). Maximum truck weight

σ = Eε

σ = $0.03 \times 30 \times 10^9$

$\frac{P}{A} =0.03 \times 30 \times 10^9$

$P = 0.03 \times 30 \times 10^9\times \frac{\pi}{4}\times (0.022)^2$

 = 342119.44 N

For the four sensors,

Maximum weight = 4 x P

                            =  4 x 342119.44

                            = 1368477.76 N

Therefore, weight in kg is $m=\frac{W}{g}=\frac{1368477.76}{9.81}$

                     m = 139498.24 kg

b). Change in resistance

k=\frac{\Delta R/R}{\Delta L/L}

$\Delta R = k. \epsilon R$    , since $\epsilon= \Delta L/ L$

$\Delta R = 6.9 \times 0.03 \times 340$

$\Delta R = 70.38 $ Ω

For 4 resistance of the sensors,

$\Delta R = 70.38 \times 4 = 281.52$ Ω

c). $k=\frac{\Delta R/R}{\epsilon}$

If linear strain,

$\frac{\Delta R}{R} \approx \frac{\Delta L}{L}$  , where k = 1

$\Delta R = \frac{\Delta L}{L} \times R$

$\Delta R = 0.03 \times 340$

$\Delta R = 10.2 $ Ω

4 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
enyata [817]

Answer:

Check image, right on PLATO

Explanation:

7 0
3 years ago
Switches are placed only in the _ of a circuit?
postnew [5]

the switch should always be placed immediately adjacent to the non-grounded terminal of the power supply.

4 0
3 years ago
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