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3 years ago

Which type of material is known as elastomers to materials scientists and engineers

Engineering

1 answer:

KIM [24]3 years ago

8 0

Answer:

Rubber-like solids with elastic properties are called elastomers. Polymer chains are held together in these materials by relatively weak intermolecular bonds, which permit the polymers to stretch in response to macroscopic stresses. Natural rubber, neoprene rubber, buna-s and buna-n are all examples of such elastomers.

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Bessy's calf weighed 99.19 pounds when calved on March 7th. Her calf gained an average of 1.85 pounds per day for 266 days. What

Zepler [3.9K]

Answer:

591.3

Explanation:

99.19 + (1.85 × 266) = 591.29

rounded = 591.3

4 0

4 years ago

Thomas Edison modification of the filament of the light bulb is an example of the "identify the problem" step of the engineering

777dan777 [17]

True , i’m pretty sure

3 0

3 years ago

TODO EMPLEADO ESTA OBLIGADO A PRESTAR SUS SERVICIOS LABORALES 72 HORAS A LA SEMANA?

grandymaker [24]

Si depende en que casos se y de que trate su trabajo pero tampoco lo pueden obligar pero como ya dije depende

6 0

3 years ago

A typical aircraft fuselage structure would be capable of carrying torsion moment. a)True b)- False

Taya2010 [7]

Answer:

True

Explanation:

An aircraft is subject to 3 primary rotations

1) About longitudinal axis known as rolling

2) About lateral axis known as known as pitching

3) About the vertical axis known as yawing

The rolling of the aircraft induces torsion in the body of the aircraft thus the fuselage structure should be capable of carrying torsion

8 0

3 years ago

The USAF is thinking of purchasing a improved automatic controller (no human required) at a cost of $100,000 that can make 4,000

blsea [12.9K]

Answer:

It would take 3225.8 hours of target detection to pay off the new controller

Explanation:

First, to find out how many hours it would take, we calculate what is the cost per contact for both options:

$\mbox{cost per contact}=\frac{\mbox{cost per hour}}{\mbox{contacts per hour}} \\\\\mbox{cost per contact}_{specialist} =\frac{8 \frac{\$}{h} }{1000\frac{contacts}{hour} } =8*10^{-3} \frac{\$}{contact}\\\\\mbox{cost per contact}_{controller} =\frac{1 \frac{\$}{h} }{4000\frac{contacts}{hour} } =2.5*10^{-4} \frac{\$}{contact}$

Knowing the cost per contact, we calculate savings per contact when using the controller:

$Savings=\mbox{cost per contact}_{specialist}-\mbox{cost per contact}_{controller}\\Savings=8*10^{-3} \frac{\$}{contact}-2.5*10^{-4} \frac{\$}{contact}=7.75*10^{-3} \frac{\$}{contact}$

Now that we know how much the automatic controller saves, we calculate how many contacts it would take to pay it off, and then, taking into account contacts per hour, how many hours:

$Hours=\frac{\mbox{cost of the controller}}{\mbox{savings per contact}}*\frac{\mbox{1}}{\mbox{contacts per hour}} \\\\Hours=\frac{\$100000}{7.75*10^{-3} \frac{\$}{contact}} *\frac{\mbox{1}}{4000\frac{contacts}{hour} }}=3225,8 \mbox{ hours}$

That means, without taking into account veteran benefits (that raise the cost of the USAF specialist), it would take around 134 days of target detection to pay off the new controller.

8 0

3 years ago