Two kilograms of air in a piston-cylinder assembly undergoes an isothermal

Engineering

1 answer:

Lubov Fominskaja [6]2 years ago

7 0

Answer:

a) 0.39795 kJ/K

b) 79.589.37 kJ

Explanation:

m = Mass of air = 2 kg

Temperature = 200 K

P₁ = Initial pressure = 300 kPa

P₂ = Final pressure = 600 kPa

R = mass-specific gas constant for air = 287.058 J/kgK

a) For isentropic process

∴ Entropy is generated in the process is 0.39795 kJ/K

∴ Amount of lost work is 79.589.37 kJ

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