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4 years ago

Which of the following is an example of velocity?

Chemistry

2 answers:

Kitty [74]4 years ago

4 0

The answer is A... Hope This helps!

Musya8 [376]4 years ago

3 0

I believe the answer is B.

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A 100g of sample of a compound is combusted in excess oxygen and the products are 2.492g of CO2 and 0.6495 of H2O. Determine the

ruslelena [56]

The empirical formula : C₁₁O₁₄O₃

<h3>Further explanation</h3>

The assumption of the compound consists of C, H, and O

mass of C in CO₂ =

$\tt \dfrac{12}{44}\times 2.492=0.680~g$

mass of H in H₂O =

$\tt \dfrac{2.1}{18}\times 0.6495=0.072~g$

mass of O :

mass sample-(mass C + mass H)

$\tt 1-(0.68+0.072)=0.248`g$

mol of C :

$\tt \dfrac{0.68}{12}=0.056$

mol of H :

$\tt \dfrac{0.072}{1}=0.072$

mol of O :

$\tt \dfrac{0.248}{16}=0.0155$

divide by 0.0155(the lowest ratio)

C : H : O ⇒

$\tt \dfrac{0.056}{0.0155}\div \dfrac{0.072}{0.0155}\div \dfrac{0.0155}{0.0155}=3.6\div 4.6\div 1\\\\\dfrac{11}{3}\div \dfrac{14}{3}\div \dfrac{3}{3}=11:14:3$

3 0

3 years ago

What is the formula of the compounds Cl- and Na+

Whitepunk [10]

Na and Cl together form the compound
NaCl2

5 0

3 years ago

Place the following substances in Order of decreasing boiling point H20 N2 CO

kirill [66]

Answer:

-195.8º < -191.5º < 100º

Explanation:

Water, or H20, starts boiling at 100ºC.

Nitrogen, or N2, starts boiling at -195.8ºC.

Carbon monoxide, or C0, starts boiling at -191.5ºC.

When we place these in order from decreasing boiling point:

-195.8º goes first, then -191.5º, and 100º goes last.

4 0

4 years ago

Read 2 more answers

Hellllppppp lons Worksheet

Iteru [2.4K]

The metals will lose electrons while the non metals will gain electrons in order to attain octet structure.

An ion can be cation (positively charged) or anion (negatively charged).

Cations attain octet structure (8) by losing electron(s) while anions become stable or attains octet structure (8) by gaining electron(s).

The remaining elements are completed as follows to attain octet structure;

Element--valence electron--electrons to gain--electrons to lose--ion formed

O ------------ 6 ---------------------- 2 ------------------------ none -------------- $O^{2-}$

Ca -------- 2 ----------------------- none ---------------------- 2 ------------------ $Ca^{2+}$

Br ----------- 7 --------------------- 1 ------------------------ none --------------- $Br^{-}$

S ------------ 6 ----------------------- 2 ------------------------ none --------------- $S^{2-}$

Cl ------------ 7 ----------------------- 1 ------------------------ none ---------------- $Cl^{-}$

K -------------- 1 ----------------------- none ----------------------- 1 ------------------ $K^{+}$

Mg ------------ 2 ---------------------- none ---------------------- 2 ---------------- $Mg^{2+}$

Be ------------- 2 ---------------------- none ---------------------- 2 ---------------- $Be^{2+}$

Learn more here: brainly.com/question/21089350

8 0

3 years ago

Consider the reaction 2 S + 3 O2 â†’ 2 SO3 , which has a 75.1% yield. How much O2 is consumed if 583 g of SO3 are produced?

Ymorist [56]

Answer:

A/1. 10.9 mol O2

Explanation:

583 g x 1 mol SO3 x 3 mol O2 /

80.057 g mol SO3 x 2 mol SO3

- You just need to find molar mass of SO3, which is 80.057 g.

- Everything else came from formula. Further explanation...

- Always start with what they give, such as 583 g. Then find 1 mol of what is being produced, in this it is SO3. We already found this because we did molar mass above. Next. find how many moles of what they want, which is O2. Look in equation and you can see 3 mol in from of O2. Next, do the same for SO3 and you can find 3 mol in front of that. Lastly, just do the math.

- If you need a further explanation or more help on any problems I would be happy to help, just let me know.

4 0

3 years ago