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8090 [49]
3 years ago
14

A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimum coefficient of static friction

between the road and the car's tires that will allow the car to travel at this speed without sliding?
A. 1.23B. 0.662C. 0.816D. 0.952E. 0.736
Physics
1 answer:
DanielleElmas [232]3 years ago
3 0

Answer:

The minimum coefficient of static friction between the road and the car's tires is 0.816

Option "C"

Explanation:

Given;

velocity of the car, v = 40.0 m/s

radius of horizontal curve, r =  200 m

For a minimum coefficient of static friction between the road and the car's tires that will allow the car to travel at the given speed without sliding, centripetal force must equal frictional force.

F_{frictional} = F_{centripetal}\\\\\mu mg = \frac{mv^2}{r} \\\\\mu = \frac{v^2}{rg}

where;

μ is the minimum coefficient of static friction

\mu = \frac{40^2}{200*9.8} \\\\\mu = 0.816

Thus, the minimum coefficient of static friction between the road and the car's tires is 0.816

Option "C"

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A tennis ball is released from a height of 4.0 m above the floor. After its third bounce off the floor, it reaches a height of 1
diamong [38]

Answer:

The percentage of its mechanical energy does the ball lose with each bounce is 23 %

Explanation:

Given data,

The tennis ball is released from the height, h = 4 m

After the third bounce it reaches height, h' = 183 cm

                                                                       = 1.83 m

The total mechanical energy of the ball is equal to its maximum P.E

                                      E = mgh

                                          = 4 mg

At height h', the P.E becomes

                                      E' = mgh'

                                           = 1.83 mg

The percentage of change in energy the ball retains to its original energy,

                                 \Delta E\%=\frac{1.83mg}{4mg}\times100\%

                                  ΔE % = 45 %

The ball retains only the 45% of its original energy after 3 bounces.

Therefore, the energy retains in each bounce is

                                   ∛ (0.45) = 0.77

The ball retains only the 77% of its original energy.

The energy lost to the floor is,

                                E = 100 - 77

                                   = 23 %

Hence, the percentage of its mechanical energy does the ball lose with each bounce is 23 %      

5 0
3 years ago
A student constructs a simple constant volume gas thermometer and calibrates it using the boiling point of water, 100°C, and the
just olya [345]

Answer:

The pressure corresponding to the absolute zero temperature is 0.997atm.

Explanation:

To solve this question, you draw a straight vertical line with the boiling point temperature and pressure on top of the line and the freezing point temperature and pressure on the lower part. The absolute temperature somewhere in the middle of the line with the pressure to be obtained.

So, we have;

0- (-19) / 100 - (-19) = P - 0.9267 / 1.366 - 0.9267

19 / 119 = P - 0.9267 / 0.4393

Cross multiply, we have

19 * 0.4393 = 119(P -0.9267)

8.3467 = 119P - 110.2773

119P = 118.624

P = 0.997 atm

So at 0°C, the pressure of the thermometer is 0.997atm.

4 0
3 years ago
What is the definition of major plates?
lutik1710 [3]

Answer:

The outer shell of the earth, the lithosphere

Explanation:

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It can be shown that Fick's law of diffusion can be adapted to find that the time for the first solute molecule to travel a dist
oee [108]

Answer:

L = 0.0464 m

Explanation:

Given;

The relation between the time 't' and the distance 'L' as:

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on substituting the values in the above relation, we get

60=\frac{L^2}{2\times1.8\times10^{-5}}

or

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Answer:

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