Answer:
The specific heat capacity of a metal is 1.31 J/g°C = C
Explanation:
A classical excersise of calorimetry to apply this formula:
Q = m . C . ΔT
177.5 J = 15 g . C (34°C - 25°C)
177.5 J = 15g . 9°C . C
177.5 J /15g . 9°C = C
1.31 J/g°C = C
Dont know if its right but :/ <span>NiS <---> Ni+2 + S-2 </span><span>Ksp = [Ni+2] * [S-2] = (9.6E=11)^2 = 9.22E-21</span>
Using the ideal gas law PV =nRTPV=nRT , we find that the pressure will be P =\frac{nRT}{V}P=
V
nRT
. Then, we'll substitute and find the pressure, using T = -25 °C = 248.15 K and R = 0.0821 \frac{atm\cdot L}{mol \cdot K}
mol⋅K
atm⋅L
:
P =\frac{nRT}{V} = \frac{(0.33\,\cancel{mol})(0.0821\frac{atm\cdot \cancel{L}}{\cancel{mol \cdot K}})(248.15\,\cancel{K})}{15.0\,\cancel{L}} = 0.4482\,atmP=
V
nRT
=
15.0
L
(0.33
mol
)(0.0821
mol⋅K
atm⋅
L
)(248.15
K
)
=0.4482atm
In conclusion, the pressure of this gas is P=0.4482 atm.
Reference:
Chang, R. (2010). Chemistry. McGraw-Hill, New York.
Answer:
Mechanical energy
Explanation:
Given that,
Potential energy of an object is given by :
P = mgh
The kinetic energy of an object is given by :
Where
m is mass
h is height
v is velocity of the object
The sum of potential and kinetic energy is equal to total energy or the mechanical energy.
Hence, if air resistance is negligible, the sum total of potential and kinetic energies of a freely falling body is equal to mechanical energy.
