Answer:
The mass of the ball is 0.23 kg
Explanation:
Given that
radius ,r= 3.74 cm
Density of the milk ,ρ = 1.04 g/cm³ = 1.04 x 10⁻³ kg/cm³
Normal force ,N= 9.03 x 10⁻² N
The volume of the ball V
V= 219.13 cm³
The bouncy force on the ball = Fb
Fb = ρ V g
Fb + N = m g
m=Mass of the ball = Density x volume
m = γ V , γ =Density of the Ball
ρ V g + N = γ V g ( take g= 10 m/s²)
γ = 0.00108 kg/cm³
m = γ V
m = 0.00108 x 219.13
m= 0.23 kg
The mass of the ball is 0.23 kg
Explanation:
(c) I assume we're looking for mA.
Sum of forces on B in the -y direction:
∑F = ma
mBg − T = mBa
Sum of forces on A in the +x direction:
∑F = ma
T = mAa
Substitute:
mBg − mAa = mBa
mBg − mBa = mAa
mA = mB (g − a) / a
Plug in values:
mA = (5 kg) (10 m/s² − 0.01 (10 m/s²)) / (0.01 (10 m/s²))
mA = 495 kg
The answer key seems to have a mistake. It's possible they meant mB = 1 kg, or they changed mB to 5 kg but forgot to change the answer.
The formula is:
v = v o + a t
6 = 10 + 3 * a
3 a = 10 - 6
a = 4 : 3
a = - 1.33 m/s² ( because the car slows down )
Answer: The average acceleration of the car is - 1.33 m/s²
