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3 years ago

13

Group 1A elements have similar properties because they___

1 answer:

kirza4 [7]3 years ago

3 0

Answer:

that is because they have a strong tendency to donate their valence electron in the last shell to form strong ionic bonds

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If 36C ofcharge pass through a write in 4s current is it carrying?

charle [14.2K]

Answer:

The current flowing through the wire is 9 A.

Explanation:

Given;

quantity of charge passing through the wire, Q = 36 C

duration of the charge flow, t = 4 s

The current flowing through the wire is calculated as;

Q = It

I = Q / t

where;

I is the current flowing in the wire

I = 36/4

I = 9 A

Therefore, the current flowing through the wire is 9 A.

8 0

3 years ago

7. An engineer is using a wire that has a resistance of 1.5 . This resistance is too high for the application he is designing. T

Veronika [31]

Answer and Explanation:

We know that resistance $R=\frac{\rho l}{A}$ from the given equation of resistance it is clear that resistance depends on resistivity length and area of the material but we can not change the length because it is given that the length must be 2.5 cm long.

So we can do two two things to reduce the resistance

increase the cross sectional area
decrease the resistivity of the material

7 0

3 years ago

Two horses begin at rest. After a few seconds, horse A is traveling with a velocity of 10 m/s west, while horse B is traveling w

viktelen [127]

It would be b kk I love horses

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3 years ago

What is the amount of force required to accelerate a 20 kg object to 5 m/s˛?

Llana [10]

Answer:

Force = 100N

Explanation:

Force = mass × acceleration

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3 years ago

A banked circular highway curve is designed for traffic moving at 58 km/h. The radius of the curve is 201 m. Traffic is moving a

skelet666 [1.2K]

Answer:0.077

Explanation:

Given

banked designed for traffic moving at $58 km/h\approx 16.11 m/s$

Radius of the curve 201 m

Actual traffic velocity = $37 km/h approx 10.27 m/s$

For banking of road

$tan\theta =\frac{v^2}{rg}$

$tan\theta =\frac{16.11^2}{201\times 9.81}$

$\theta =7.49^{\circ}$

Centripetal acceleration is given by

$a=\frac{v^2}{r}$

Taking component of centripetal acceleration

along and perpendicular to surface

$a_{parallel}=\frac{v^2cos\theta }{r}$

$a_{perpendicular}=\frac{v^2sin\theta }{r}$

From FBD

$mgsin\theta -f_s=ma_{parallel}$

$f_s=mgsin\theta -ma_{parallel}$ ----1

where $f_s$ is frictional force

$N-mgcos\theta =ma_{perpedicular}$

$N=mgcos\theta +ma_{perpedicular}$ ----2

and we know coefficient of friction is given by

$\mu =\frac{f_s}{N}$

$\mu =\frac{mgsin\theta -ma_{parallel}}{mgcos\theta +ma_{perpedicular}}$

$\mu =\frac{gsin\theta -\frac{v^2cos\theta }{r}}{gcos\theta +\frac{v^2sin\theta }{r}}$

$\mu =\frac{1.2804-0.5202}{9.726+0.068}$

$\mu =0.077$

7 0

3 years ago