1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alisha [4.7K]
4 years ago
14

Express the equilibrium constant for the following reaction.P(g) + 3/2 Cl2(g) ↔ PCl3(g)K = [PCl3]^2/[P]^2[Cl2]^3K = [PCl3]/[P][C

l2]^3/2K = [P][Cl2]^3/2/[PCl3]K = [P]^1/2[Cl2]^1/3/[PCl3]^1/2K = [PCl3]^2/[P]2[Cl2]3
Chemistry
2 answers:
elixir [45]4 years ago
5 0

Answer:

b) K = [PCl3] / [P][Cl2]∧(3/2)

Explanation:

  • P(g) + 3/2 Cl2(g) ↔ PCl3(g)

equlibrium constant (K):

⇒ K = [PCl3] / [P].[Cl2]∧(3/2)

Afina-wow [57]4 years ago
5 0

Answer:

K = [PCl3]/[Cl2]^3/2[P]

Explanation:

To get an expression for the equilibrium constant, we simply place the concentrations of both the reactants and the product in terms of square bracket and raise them to the power of their coefficients in the balanced equations.

After doing this we place the expression of the product over that of the reactant.

K = [PCl3]/[Cl2]^3/2[P]

You might be interested in
For lunch today, I ate an apple. What type of carbohydrate did I ingest?
mafiozo [28]

Answer:

Monosaccharide

Explanation:

Apples contain high levels of fructose, which is a monosaccharide.

8 0
4 years ago
Help please! It’s the pmas
umka21 [38]

Answer:

choice 3

Explanation:

homeostasis is the ability of an organism to remain in balance so for two systems two show homeostasis pick the choice that shows two separate systems working together for a common goal in this case breathing.

6 0
3 years ago
A 2.600×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in w
sesenic [268]

Answer:

A. 0.2395 w/w %

B. 2394ppm

Explanation:

A. To find concentrationin percent by mass of the solution we need to calculate mass of glycerol and mass of water. The formula is:

Mass glycerol / Total mass * 100

<em>Mass glycerol:</em>

The solution is 2.6x10⁻²moles / L. As there is 1L of solution there are 2.6x10⁻² moles of glycerol. In mass (Using molar mass glycerol: 92.09g/mol):

2.6x10⁻² moles of glycerol * (92.09g / mol) = 2.394g glycerol

<em>Mass of water:</em>

998.9mL and density = 0.9982g/mL:

998.9mL * (0.9982g/mL) = 997.1g of water.

That means percent by mass is:

% by mass: 2.394g / (997.1g + 2.394g) * 100 = 0.2395 w/w %

B. Parts per million are mg of glycerol per L of solution. As in 1L there are 2.394g. In mg:

2.394g * (1000mg / 1g) = 2394mg:

Parts per million: 2394mg / L = 2394ppm

3 0
3 years ago
Write a balanced chemical equation for the standard formation reaction of gaseous formaldehyde CH2O
Ymorist [56]
From the combustion of octane, the formaldehyde will be formed as this equation:

C8H18 +  O2 → CH2O + H2O   this is the original equation but it is not a balanced equation, so let's start to balance it: 

the equation to be balanced so the number of atoms on the right side of the equation sholud be equal with the number of atoms on the lef side.

-we have 8 C atoms on left side and 1 atom on the right side so we will try putting 8 CH2O on the right side instead of CH2O

C8H18 + O2 → 8 CH2O + H2O 

we have 2 O atoms on the left side and  9 atoms on the right side so we will try first to put 9 O2 instead of O2 on the left side and put 2H2O on the right side and put  16 CH2O instead of 8 CH2O to make the atoms of O are equal on both sides = 18 atoms

C8H18 + 9 O2 →  16 CH2O + 2H2O 

put now we have 8 atom C on the left side and 16 atom on the right side so, we will put 2 C8H18 instead of C8H18 now we get this equation:

2C8H18 + 9O2 →16 CH2O + 2H2O

-now we have 36 of H atoms on both sides.

- and 16 of C atoms on both sides.

- and 18 of O atoms on both sides.

now all the number of atoms of O & C & H are equal on both sides

∴ 2C8H18 + 9O2 → 16 CH2O + 2 H2O 

is the final balanced equation for the formation of formaldehayde
8 0
4 years ago
Which is the more preferred fuel: one with a higher energy density or one with a lower energy density
Nana76 [90]

The higher the energy density of a fuel, the greater the amount of energy it has stored.

<h3>What is the energy density?</h3>

The energy density of a fuel is defined as the amount of energy it possesses per unit volume or per unit weight.

<h3>Characteristics of the energy density</h3>

  • It is the amount of energy accumulated in an energy vector per unit volume or mass.

  • In general, higher density energy sources and carriers are preferable, as many end uses require concentration of such energy.

  • The packaging of energy in liquid hydrocarbons is the one with the highest energy density, that is, the highest energy per volume unit, hence its high use in the transportation sector.

Therefore, we can conclude that in general, fuels, especially low molecular weight fuels, have high energy densities.

Learn more about the energy density here: brainly.com/question/2165966

5 0
3 years ago
Other questions:
  • Which ions are spectator ions in the formation of a precipitate of agcl via combining aqueous solutions of cocl2 and agno3?
    15·1 answer
  • Which of the following energy sources are in some way divided from the sun (select all that apply)
    9·1 answer
  • Which health condition is an infectious disease
    5·2 answers
  • Which ones can be separated or made into a simpler substance?
    14·1 answer
  • When comparing two gases to determine which one is closest to an ideal gas, which strategy is best? A. Look up the van der Waals
    8·1 answer
  • What types of medicines are causing problems when improperly disposing of them?
    14·1 answer
  • How does an increase in concentration affect the rate of a reaction?
    9·1 answer
  • What is the molality of a solution of Al(C103), in water that boils at 103.82°C (K) = 0.512°C/m)?
    11·1 answer
  • Last post as a troll lol, sorry but i need actual help this time.
    15·2 answers
  • What is the ph of the solution formed by mixing 25. 0 ml of a 0. 15 m solution of nh3 with 25. 0 ml of 0. 12 m hcl? (kb for nh3
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!