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Salsk061 [2.6K]
3 years ago
13

Which of the following is the best way to make a conclusion? A. The experiment must be manipulated until the results show what y

ou want B. Estimate results to where they should be C. Choosing the results you like best D. Comparing data from the experiment to
Physics
1 answer:
Genrish500 [490]3 years ago
7 0

Answer:

D

Explanation:

You should compare your results and data with your original hypothesis.  It is okay to have a hypothesis that was shown to be false.  That's science. Things do not always work out.  You can always discuss what you could have done differently and things that went wrong.  There is no right answer in science!

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The intensity of sunlight reaching the earth is 1360 w/m2. Assuming all the sunligh is absorbed, what is the radiation pressure
krok68 [10]

(a) 1.15\cdot 10^9 N

For an electromagnetic wave incident on a surface, the radiation pressure is given by (assuming all the radiation is absorbed)

p=\frac{I}{c}

where

I is the intensity

c is the speed of light

In this problem, I=1360 W/m^2; substituting this value, we find the radiation pressure:

p=\frac{1360 W/m^2}{3\cdot 10^8 m/s}=4.5\cdot 10^{-6} Pa

the force exerted on the Earth depends on the surface considered. Assuming that the sunlight hits half of the Earth's surface (the half illuminated by the Sun), we have to consider the area of a hemisphere, which is

A=2pi R^2

where

R=6.37\cdot 10^6 m

is the Earth's radius. Substituting,

A=2\pi (6.37\cdot 10^6 m)^2=2.55\cdot 10^{14}m^2

And so the force exerted by the sunlight is

F=pA=(4.5\cdot 10^{-6} Pa)(2.55\cdot 10^{14} m^2)=1.15\cdot 10^9 N

(b) 3.2\cdot 10^{-14}

The gravitational force exerted by the Sun on the Earth is

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M=1.99\cdot 10^{30}kg is the Sun's mass

m=5.98\cdot 10^{24}kg is the Earth's mass

r=1.49\cdot 10^{11} m is the distance between the Sun and the Earth

Substituting,

F=(6.67\cdot 10^{-11} )\frac{(1.99\cdot 10^{30}kg)(5.98\cdot 10^{24} kg)}{(1.49\cdot 10^{11} m)^2}=3.58\cdot 10^{22}N

And so, the radiation pressure force on Earth as a fraction of the sun's gravitational force on Earth is

\frac{1.15\cdot 10^9 N}{3.58\cdot 10^{22}N}=3.2\cdot 10^{-14}

6 0
4 years ago
Which vector correctly indicates the direction of centripetal acceleration experienced by the car?
gogolik [260]

The answer is C.

I hope this helped!

5 0
3 years ago
Read 2 more answers
Name two examples where the cohesive force dominates over the adhesive force and vice versa​
lidiya [134]
Attractive forces between molecules of the same type are called cohesive forces. ... Attractive forces between molecules of different types are called adhesive forces. Such forces cause liquid drops to cling to window panes, for example.
5 0
3 years ago
Calculate the energy released as heat when 51.60 g Cu 2 O ( s ) undergo oxidation at constant pressure.
lesya692 [45]

Answer:

Energy released as heat will be -189.417 Kj

Explanation:

The oxidation is the type of reaction in which reaction occurs in the presence of oxygen. The exothermic reaction is the type of reaction in which heat is released. The enthalpy is the type of physical quantity that is used to measure the energy in the thermodynamic system.

As we know the molar mass of Copper II Oxide is 79.545 g

Also the oxidation of  copper(II) oxide, CuO(s), is an exothermic process, 2Cu2O (s) + O2-->4CuO (s) delta H reaction= -292.0 kj/mol.

So for 51.60g of Copper II Oxide,

Heat released will be (-292.0 * 51.60/79.545) = -189.417 Kj

6 0
3 years ago
2 Points
Tamiku [17]

Answer:

A. 0.32s

Explanation:

Lets find the initial velocity of the vertical component

Cos23=u/4

4cos23=1.6m/s

then time, t =2u/g

2×1.6/9.8

=0.32seconds

6 0
3 years ago
Read 2 more answers
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