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topjm [15]
3 years ago
13

Determine the electrical force of attraction between two balloons with separate charges of +3.5 × 10-8 C and -2.9 × 10-8 C when

separated a distance of 0.65 m.
Physics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

The electrical force of attraction between the balloons is 2.16\times 10^{-5}\ N.

Explanation:

Given that,

Charge 1, q_1=+3.5\times 10^{-8}\ C

Charge 2, q_2=-2.9\times 10^{-8}\ C

Distance between the charges, d = 0.65 m

We need to find the electrical force of attraction between two balloons. It is given by the formula as :

F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{3.5\times 10^{-8}\times 2.9\times 10^{-8}}{(0.65)^2}\\\\F=2.16\times 10^{-5}\ N

So, the electrical force of attraction between the balloons is 2.16\times 10^{-5}\ N. Hence, this is the required solution.

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"what is the horse's average velocity during the first ten seconds of its gallop
vladimir1956 [14]

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, from the completed question, determine the distance (in meters) the horse covered in the first ten seconds of it's gallop and apply the formula below.

Average velocity = distance (in meters) ÷ time (in seconds as provided in this question)

The unit for velocity (to be used here) is m/s or ms⁻¹

6 0
3 years ago
You are a member of an alpine rescue team and must get a box of supplies, with mass 3 kg , up an incline of constant slope angle
denis23 [38]

Answer:

v = 9.04 m / s

Explanation:

For this exercise we can use the relation that the work of the non-conservative force (friction) is equal to the variation of the mechanical energy of the system.

          W = Em_f - Em₀         (1)

Starting point. Lower slope

        Em₀ = K = ½ m v²

highest point. Where is the skier at a height h

        Em_f = U = m g h

The work of rubbing

        W = -fr x

the negative sign is because the friction force opposes the movement.

Let's set a reference system where the x axis is parallel to the slope and the y axis is perpendicular

let's use trigonometry to break down the weight

        cos θ = W_y / W

        sin θ = Wₓ / W

        W_y = W cos θ

        Wₓ = W sin θ

Y axis

        N - Wₓ = 0

        N = mg sin  θ

X axis

         fr = m a

the friction force has the expression

         fr = μ N

         fr = μ mg sin θ

we look for the job

         W = - μ mg sin θ  x

where x is the distance along the slope

       

we substitute in 1

         -μ mg sin θ x = mg h - ½ m v²

let's use trigonometry to find the distance x

        tan 30 = h / x

        x = h / tan 30

we substitute

          -   \mu \ mg \ sin \theta \  \frac{h}{tan 30} \ x = m gh - ½ m v²

we use  

          tan 30 = sin30 / cos30

         

          v² = 2g h + 2 μ g h cos 30

          v = \sqrt{ 2gh \ (1+ cos 30}

let's calculate

          v = \sqrt{ 2 \ 9.8 \ 4 \ (1 + 0.05 \ cos \ 30)}

          v = 9.04 m / s

4 0
3 years ago
Is magnitude a direction or numeric value​
dolphi86 [110]
It is an numeric value
6 0
3 years ago
Famed stunt pilot, Cleonvia Thread, pulls out rapidly from a dive. He is traveling at 222 mi/h at the bottom of his trajectory,
Simora [160]

Answer:

0.39 m/s²

Explanation:

From the question,

a = v²/r.................... Equation 1

Where v = velocity, r = radius.

Given: v = 222 mi/h = (222×0.44704) m/s = 9.83 m/s, r = 820 ft = (820×0.3048) m = 249.94 m.

Substitute thses values into equation 1

a = 9.83²/249.94

a = 96.63/249.94

a = 0.39 m/s²

Hence the  acceleration is 0.39 m/s²

8 0
3 years ago
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stealth61 [152]

Answer:

The displacement of the photographer and the astronauts are equal

Explanation:

In this exercise, it is important to differentiate between distance and displacement.

The distance moved by an object describes the total length of change in position irrespective of the objects starting point or the point where the transit stops. Distance is a scalar quantity as it does not specify a direction of which a transit takes place as such a piston moving in oscillatory motion can be said to cover a very long distance considering its number of completed cycles

Displacement unlike distance is a vector quantity which accounts for an objects starting and ending points regardless of the route through which the object completed the distance, as such it is the straight line linking the object starting and stopping points, of which the length of the line is the magnitude of displacement and the direction from the starting point to the end point

As such in the above question the displacement of the photographer is his transit from Florida to California while the displacement of the astronauts is also from Florida and stopping at California both of which are equal

6 0
3 years ago
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