Answer:
This question is incomplete
Explanation:
This question is incomplete. However, from the completed question, determine the distance (in meters) the horse covered in the first ten seconds of it's gallop and apply the formula below.
Average velocity = distance (in meters) ÷ time (in seconds as provided in this question)
The unit for velocity (to be used here) is m/s or ms⁻¹
Answer:
v = 9.04 m / s
Explanation:
For this exercise we can use the relation that the work of the non-conservative force (friction) is equal to the variation of the mechanical energy of the system.
W = Em_f - Em₀ (1)
Starting point. Lower slope
Em₀ = K = ½ m v²
highest point. Where is the skier at a height h
Em_f = U = m g h
The work of rubbing
W = -fr x
the negative sign is because the friction force opposes the movement.
Let's set a reference system where the x axis is parallel to the slope and the y axis is perpendicular
let's use trigonometry to break down the weight
cos θ = W_y / W
sin θ = Wₓ / W
W_y = W cos θ
Wₓ = W sin θ
Y axis
N - Wₓ = 0
N = mg sin θ
X axis
fr = m a
the friction force has the expression
fr = μ N
fr = μ mg sin θ
we look for the job
W = - μ mg sin θ x
where x is the distance along the slope
we substitute in 1
-μ mg sin θ x = mg h - ½ m v²
let's use trigonometry to find the distance x
tan 30 = h / x
x = h / tan 30
we substitute
-
= m gh - ½ m v²
we use
tan 30 = sin30 / cos30
v² = 2g h + 2 μ g h cos 30
v = 
let's calculate
v = 
v = 9.04 m / s
Answer:
0.39 m/s²
Explanation:
From the question,
a = v²/r.................... Equation 1
Where v = velocity, r = radius.
Given: v = 222 mi/h = (222×0.44704) m/s = 9.83 m/s, r = 820 ft = (820×0.3048) m = 249.94 m.
Substitute thses values into equation 1
a = 9.83²/249.94
a = 96.63/249.94
a = 0.39 m/s²
Hence the acceleration is 0.39 m/s²
Answer:
The displacement of the photographer and the astronauts are equal
Explanation:
In this exercise, it is important to differentiate between distance and displacement.
The distance moved by an object describes the total length of change in position irrespective of the objects starting point or the point where the transit stops. Distance is a scalar quantity as it does not specify a direction of which a transit takes place as such a piston moving in oscillatory motion can be said to cover a very long distance considering its number of completed cycles
Displacement unlike distance is a vector quantity which accounts for an objects starting and ending points regardless of the route through which the object completed the distance, as such it is the straight line linking the object starting and stopping points, of which the length of the line is the magnitude of displacement and the direction from the starting point to the end point
As such in the above question the displacement of the photographer is his transit from Florida to California while the displacement of the astronauts is also from Florida and stopping at California both of which are equal