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kobusy [5.1K]
3 years ago
7

Whate type of wave is made up of a sine wave plus all of its odd harmonics?

Physics
1 answer:
slega [8]3 years ago
4 0
If the phase and magnitude of each harmonic is just right, you can make a 'square wave' with those.
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Your're sailing a boat from spain west to florida. which winds would you use?
timurjin [86]
The wind you would use to travel from Spain west to Florida are The Trade Winds
6 0
3 years ago
A student charges a balloon and then brings it near a metal sphere hanging from the
Hunter-Best [27]

Answer:

B

Explanation:

the balloon has a negative charge and the metal sphere has a positive charge

3 0
3 years ago
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9. A wave on Beaver Dam Lake passes by two docks that are 40.0 m apart.
Kobotan [32]

Answers:

a) 10 m

b) time=1.6 s, frquency=0.625 Hz

c) 6.25 m/s

Explanation:

a) If there is a crest at each dock and another three crests between the two docks, and the wavelength \lambda is the distance between to crests; this means we have 4\lambda in 40 m:

40 m=4\lambda

Clearing \lambda:

\lambda=\frac{40 m}{4}

\lambda=10 m

b) This part can be solved by a Rule of Three:

If 10 waves ---- 16 s

1 wave ----- T

Then:

T=\frac{(1 wave)(16 s)}{10 waves}

T=1.6 s This is the period of the wave

On the other hand, the frequency f of the wave has an inverse relation with its period T:

f=\frac{1}{T}

f=\frac{1}{1.6 s}

f=0.625 Hz This is the frequency of the wave

c) The speed v of a wave is given by the following equation:

v=\frac{\lambda}{T}

v=\frac{10 m}{1.6 s}

Finally:

v=6.25 m/s

4 0
3 years ago
100 POINTS! I will mark brainliest! Record your hypothesis as an “if, then” statement for the rate of dissolving the compounds:
love history [14]

Answer:

<u><em>Rate of dissolving compounds:</em></u>

If we increase the temperature of the solution, then the dissolving compound would dissolve more easily.

<u><em>Boiling Point of Compounds:</em></u>

If the inter-molecular forces of any compound is really strong, then the boiling point of the compound would be really high.

6 0
3 years ago
A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.10 104 rad/s to an angular speed of 3.14
Anestetic [448]

Answer:

3.63 s

Explanation:

We can solve the problem by using the equivalent SUVAT equations for the angular motion.

To find the angular acceleration, we can use the following equation:

\omega_f^2 - \omega_i ^2 =2 \alpha \theta

where

\omega_f = 3.14\cdot 10^4 rad/s is the final angular speed

\omega_i = 1.10 \cdot 10^4 rad/s is the initial angular speed

\theta= 2.00 \cdot 10^4 rad is the angular distance covered

\alpha is the angular acceleration

Re-arranging the formula, we can find \alpha:

\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}=\frac{(3.14\cdot 10^4 rad/s)^2-(1.10\cdot 10^4 rad/s)^2}{2(2.00\cdot 10^4 rad)}=2.16\cdot 10^4 rad/s^2

Now we want to know the time the bit takes starting from rest to reach a speed of \omega_f=7.85\cdot 10^4 rad/s. So, we can use the following equation:

\alpha = \frac{\omega_f-\omega_i}{t}

where:

\alpha=2.16\cdot 10^4 rad/s^2 is the angular acceleration

\omega_f = 7.85\cdot 10^4 rad/s is the final speed

\omega_i = 0 is the initial speed

t is the time

Re-arranging the equation, we can find the time:

t=\frac{\omega_f-\omega_i}{\alpha}=\frac{7.85\cdot 10^4 rad/s-0}{2.16\cdot 10^4 rad/s^2}=3.63 s

4 0
3 years ago
Read 2 more answers
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