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saveliy_v [14]
4 years ago
12

Transcranial magnetic stimulation (TMS) is a noninvasive technique used to stimulate regions of the human brain. A small coil is

placed on the scalp, and a brief burst of current in the coil produces a rapidly changing magnetic field inside the brain. The induced emf can be sufficient to stimulate neuronal activity. One such device generates a magnetic field within the brain that rises from zero to 1.0 T in 100 ms. Determine the magnitude of the induced emf within a circle of tissue of radius 1.6 mm and that is perpendicular to the direction of the field.
Physics
1 answer:
Xelga [282]4 years ago
8 0

Answer:

7.3114*10^{-5}V

Explanation:

To give a solution to the exercise, it is necessary to consider the concepts related to magnetic flux and Faraday's law of induction. Faraday's law states that the voltage induced in a closed circuit is directly proportional to the speed with which the magnetic flux that crosses any surface with the circuit as an edge changes over time.

It is represented under the equation,

\epsilon = N \frac{\Delta\Phi}{\Delta t}

Where,

\epsilonis the induced electromotive force

N = Number of loops

\Delta t= Time

\Delta\Phi= Magnetic Flux

For definition the change in magnetic flux is:

\Delta \Phi = \Delta B A cos\phi

Where,

B= Magnetic field

Substituting at the first equation we have

\epsilon = N \frac{\Delta B A Cos\phi}{\Delta t}

\epsilon = N \frac{(B_2-B_1) (\pi r^2) Cos\phi}{\Delta t}

Our values are given by,

N = 1 turn

B_2 = 1T

B_1 = 0T

r = 1.6mm

\phi = 0\°

\Delta t = 100ms

Replacing,

\epsilon = (1) \frac{(1-0) (\pi (1.6*10^{-3})^2) Cos(0)}{110*10^{-3}}

\epsilon = 7.311*10^{-5}V

<em>Therefore the magnitud of the induced emf around a horizontal circle of tissue is 7.3114*10^{-5}V</em>

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An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally
amid [387]

The tension in the supporting cable when the cab originally moves downward is 18422.4 N

What is tension?

Tension is described as the pulling force by the means of a three-dimensional object.

Tension might also be described as the action-reaction pair of forces acting at each end of said elements.

Here,

m =combined mass = 1600 kg

s = Displacement of the elevator = 42 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 12 m/s

v = Final velocity = 0

According to the equation of motion:

v^{2} - u^{2} = 2as

0 - 12^2 = 2*a*42

a = - 144 / 84

a = - 1.714 m/s^2

Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:

T-mg = ma

T = m(g-a)

T = 1600 ( 9.8-(-1.74))

T=18422.4 N

Hence,

The tension in the supporting cable when the cab, originally moving downward is 18422.4 N

Learn more about tension here:

<u>brainly.com/question/13772148</u>

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6 0
2 years ago
If u shine a light of frequency 375Hz on a double slit setup, and u measure the slit separation to be 950nm and the screen dista
xxMikexx [17]

Answer:

Y = 3.39 x 10⁶ m

Explanation:

We will use Young's Double Slit formula here:

Y = \frac{\lambda L}{d}

where,

Y = Fringe spacing = ?

λ = wavelength = \frac{speed\ of\ light}{frequency} = \frac{3\ x\ 10^8\ m/s}{375\ Hz} = 8 x 10⁵ m

L = screend distance = 4030 nm = 4.03 x 10⁻⁶ m

d = slit separation = 950 nm = 9.5 x 10⁻⁷ m

Therefore,

Y = \frac{(8\ x\ 10^5\ m)(4.03\ x\ 10^{-6}\ m)}{9.5\ x\ 10^{-7}\ m}

<u>Y = 3.39 x 10⁶ m</u>

6 0
3 years ago
A convex mirror of focal length 34 cm forms an image of a soda bottle at a distance of 18 cm behind the mirror. The height of th
Mademuasel [1]
<h2>Answers:</h2>

In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .

<h2 /><h2>a) Position of the soda bottle (the object) </h2><h2 />

The Mirror equation is:

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}   (1)

Where:

f is the focal distance

u is the distance between the object and the mirror  

v is the distance between the image and the mirror

 

We already know the values of f and v, let's find u from (1):

u=\frac{v.f}{v-f}   (2)

Taking into account the explanation at the beginign of this asnswer:

f=-34cm and v=-18cm

The <u>negative signs</u> indicate the <u>focal distance</u> and the <u>distance between the image and the mirror are virtual </u>

Then:

u=\frac{(-18cm)(-34cm)}{-18cm-(-34cm)}  

u=38.25cm (3) >>>>Position of the soda bottle

<h2>b) magnification of the image </h2><h2 />

The magnification m of the image is given by:

m=-\frac{v}{u} (4)

m=-\frac{(-18cm)}{38.25cm}  

m=0.47 (5)>>>the image is 0.47 smaller than the object

<h2>The fact that this value is positive means the image is upright </h2>

<h2>c) Describe the image </h2><h2 />

According to the explanations and results obtained in the prior answers, the correct option is 9:

<h2>The image is <u>virtual, upright, smaller</u> than the object </h2><h2 /><h2>d) Height of the soda bottle (object) </h2>

Another way to find the magnification is by the following formula:

m=\frac{h_{i}}{h_{o}} (6)

Where:

h_{i} is the image height

h_{o} is the object height

We already know the values of m and h_{i}, let's find h_{o}:

h_{o}=\frac{h_{i}}{m} (7)

h_{o}=\frac{6.8cm}{0.47}  

h_{o}=14.46cm (8) >>>height of thesoda bottle

6 0
3 years ago
A jet aircraft with mass of 658,055 kilograms is flying straight downward. At an instant the plane's engine is producing an down
sdas [7]

Answer:

The acceleration of the plane is 10.93 m/s² at that instant.

Explanation:

Given:

Mass of aircraft, m=658055\textrm{ kg}

Downward thrust produced, F=1484732.5\textrm{ N}

Upward resistance force by air, F_{R}=740492.6\textrm{ N}

Weight of the aircraft acting donward, W=mg=658055\times 9.8=6448939\textrm{ N}

According to Newton's second law, net force acting on an object is equal to the product of mass and its acceleration.

Here, the net force is given as the difference of downward forces and upward forces.

F_{net}= F+W-F_{R}\\ F_{net}=1484732.5+6448939-740492.6=7193178.9\textrm{ N}

Now,

F_{net}=ma\\7193178.9=658055a\\a=\frac{7193178.9}{658055}=10.93\textrm{ }m/s^{2}

Therefore, the acceleration of the plane is 10.93 m/s² at that instant.

3 0
4 years ago
Table sugar has the chemical formula
Gelneren [198K]

Explanation:

This information is contained in the subscripts after each element. A molecule of sucrose (C12H22O11) has 12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms. The subscripts also indicate the ratios of the elements. A dozen CO2 molecules have one dozen carbon atoms and two dozen oxygen atoms.

7 0
3 years ago
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