The energy required to raise the temperature of 3 kg of iron from 20° C to 25°C is 6,750 J( Option B)
<u>Explanation:</u>
Given:
Specific Heat capacity of Iron= 0.450 J/ g °C
To Find:
Required Energy to raise the Temperature
Formula:
Amount of energy required is given by the formula,
Q = mC (ΔT)
Solution:
M = mass of the iron in g
So 3 kg = 3000 g
C = specific heat of iron = 0.450 J/ g °C [ from the given table]
ΔT = change in temperature = 25° C - 20°C = 5°C
Plugin the values, we will get,
Q = 3000 g × 0.450 J/ g °C × 5°C
= 6,750 J
So the energy required is 6,750 J.
Uh, not sure if you're asking or not, but during beta decay TI-207 emits a beta particle.
<h3>Answer;</h3>
A. NAD+,FAD, and NADP+
<h3><u>Explanation;</u></h3>
- Catabolic pathways breakdown molecules into smaller units that are either oxidized to release energy or used in other anabolic reactions.
- <em><u>Catabolic pathways create energy for the cell. The goal of catabolic pathways is to take energy out of molecules such as glucose,fatty acids and amino acids and store it in energy carriers (ATP) and electron carriers like NAD and Flavin-Adenine Dinucleotide (FAD) and also NADP+.</u></em>