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Ahat [919]
3 years ago
11

Will walks his dog around the block he spend an hour walking and make it 4km what is there speed

Chemistry
1 answer:
Misha Larkins [42]3 years ago
7 0
Speed = distance ÷time
speed = 4÷1=4
the answer is 4 km/hour
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The density of sea water is 1.029 kilograms per liter. What is the density of
Lelu [443]
1029 grams per kilometer
5 0
3 years ago
Describe the arrangement and movement of the octane molecules when it is a liquid​
Allisa [31]

Answer:

Particles in a liquid move randomly and can slide past each other but they don't move far away from each other. Particles in liquids are close together, rolling over each other and arranged randomly. Particles in a solid vibrate in all directions but cannot move out of their fixed positions.

Explanation:

yuh

8 0
3 years ago
A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Ca
umka21 [38]

Answer:

W = 6.65 \cdot 10^{6} lbf

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

W = m\cdot g   (1)

Where m the mass and g is the gravity  

Also, we have that the mass is:

m = \rho*V  (2)    

Where ρ is the density and V the volume

We cand calculate the volume as follows:

V = L*w*d   (3)

Where L is the length, w is the wide and d is the depth  

By entering equation (2) and (3) into (1) we have:

W = \rho*L*w*d*g

W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}  

W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf              

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

6 0
4 years ago
You mix 265.0 mL of 1.20 M lead(II) nitrate with 293 mL of 1.55 M potassium iodide. The lead(II) iodide is insoluble. What amoun
slava [35]

Answer:

105 grams PbI₂

Explanation:

Pb(NO₃)₂ + 2KI => 2KNO₃ + PbI₂(s)

moles Pb(NO₃)₂ = 0.265L(1.2M) = 0.318 mole

moles KI = 0.293(1.55M) = 0.454 mole => Limiting Reactant

moles PbI₂ from mole KI in excess Pb(NO₃)₂ = 1/2(0.454 mole) = 0.227 mol PbI₂

grams PbI₂ = 0.227 mol PbI₂ x 461 g/mole = 104.68 g ≈ 105 g PbI₂(s)

7 0
3 years ago
Read 2 more answers
What is the volume of a sample of liquid mercury that has a mass of 76.2g, given that the density of mercury is 13.6g/mL?
nignag [31]
Hey there!

D  = m / V

13.6 = 76.2 / V

V = 76.2 / 13.6

V = 5.602 mL
8 0
3 years ago
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