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Llana [10]
4 years ago
6

You are caring for the freshwater aquarium of a friend while they are on vacation. You are told to check the pH of the tank and

make sure that it stays between 6.5 and 7.0. When you check the water the pH is 8.0. The water in the tank is:
Chemistry
1 answer:
aivan3 [116]4 years ago
4 0

Answer:

The water in the tank is basic.

Explanation:

Acidity or basicity of an aqueous solution is determined through it pH value.

pH=-log[H^{+}] , where [H^{+}] is concentration of H^{+} (in molarity) in solution.

As a matter of fact, a pH scale has been established such as:

          Acidic (0\leqslant pH), Neutral (pH=7) and Basic (7)

As pH = 8.0 lies in the basic range of pH scale therefore the water in the tank is basic.

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The pressure of 5.00 L of gas increases from 1.50 atm to 1240 mmHg. What is the final volume of the gas, assuming constant tempe
Vsevolod [243]
(P1)(V1)=(P2)(V2)
(1.50)(5.00)=(1240/760)(V2)
(7.5)/(1240/760)=V2
V2=4.596774194 L
5 0
3 years ago
Read 2 more answers
The gauge pressure inside a vessel is ‐40kPa, at an elevation of 5000m. a) What is the absolute pressure? b) At this elevation,
hoa [83]

Answer:

a) Pabs = 48960 KPa

b) T = 433.332 °C

Explanation:

  • Pabs = Pgauge + d*g* h

∴ d = 1000 Kg/m³

∴ g = 9.8 m/s²

∴ h = 5000 m

∴ P gauge = - 40 KPa * ( 1000 Pa / KPa ) = - 40000 Pa; Pa≡Kg/m*s²

⇒ Pabs = - 40000 Kg/ms² + ( 1000 Kg/m³ * 9.8 m/s² * 5000 m )

⇒ Pabs = 48960000 Pa = 48960 KPa

a) at that height and pressure, we find the temperature at which the water boils by means of an almost-exponential graph which has the following equation:

P(T) = 0.61094 exp ( 17.625*T / ( T + 243.04 ))......P (KPa) ∧ T (°C)....from literature

∴ P = 48960 KPa

⇒ ( 48960 KPa / 0.61094 ) = exp ( 17.625T / (T+ 243.04))

⇒ 80138.803 = exp ( 17.625T / ( T + 243.04))

⇒ Ln ( 80138.803) = 17.625T / ( T + 243.04))

⇒ 11.292 * ( T + 243.04 ) = 17.625T

⇒ 11.292T + 2744.289 = 17.625T

⇒ 2744.289 = 17.625T - 11.292T

⇒ 2744.289 = 6.333T

⇒ T = 433.332 °C

3 0
3 years ago
What is the weight of:
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Iron = 3 × 55.845 = 167.535 g/mol

CaCO3 = 20 × 100.0869 = 2001.738 g/mol

8 0
3 years ago
4 NH3 + 6 NO → 5 N2 + 6 H2O How many moles of NH3 are necessary to produce 0.824 mol N2?
GrogVix [38]
4 mol NH₃ → 5 mol N₂
x mol NH₃ → 0.824 mol N₂

x=0.824*4/5=0.6592 mol
6 0
4 years ago
How many grams are there in 2.00 moles of copper (ii) oxide
tatuchka [14]

Answer: 159 grams

Explanation:

Copper (ii) oxide has the chemical formula CuO.

Now given that:

Mass of CuO in grams = ? (let unknown value be Z)

Number of moles = 2.00 moles

Molar mass of CuO = ?

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= 63.5g + 16g

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Apply the formula:

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Z = 79.5 g/mol x 2.00 moles

Z = 159g

Thus, there are 159 grams in 2.00 moles of copper (ii) oxide

7 0
3 years ago
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