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Reil [10]
3 years ago
9

Select the correct answer. Based on the reactivities of the elements involved, which reaction will form products that are more s

table than the reactants? A. 2AlBr3 + 3Zn → 3ZnBr2 + 2Al B. CaBr2 + 2Na → 2NaBr + Ca C. MgBr2 + H2 → 2HBr + Mg D. BaBr2 + Ca → CaBr2 + Ba E. 2LiBr + Ba → BaBr2 + 2Li Reset Next Post Test: Chemical Reactions

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
8 0

Answer: The correct answer is option B.

Explanation: Reactivity of elements is defined as the tendency to loose or gain electrons.

These reactions are a type of single displacement reactions. A single displacement reaction is a type of reaction in which an element displaces another element in a chemical reaction. These are studied with the help of reactivity series.

The element which lies above in the reactivity series can easily displace the element which lies below in the reactivity series.

Option A: This reaction will not yield a stable product because Zinc lies below Aluminium in the reactivity series.

AlBr_3+Zn\rightarrow \text{No reaction}

Option B: This reaction will yield a stable product because Sodium lies above Calcium in the reactivity series.

CaBr_2+2Na\rightarrow 2NaBr+Ca

Option C: This reaction will not yield a stable product because Hydrogen lies below Magnesium in the reactivity series.

MgBr_2+H_2\rightarrow \text{No reaction}

Option D: This reaction will not yield a stable product because Calcium lies below Barium in the reactivity series.

BaBr_2+Ca\rightarrow \text{No reaction}

Option E: This reaction will not yield a stable product because barium lies below Lithium in the reactivity series.

2LiBr+Ba\rightarrow \text{No reaction}

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For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
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Now we need to calculate the pKa2

pKa2 = -log Ka

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We know Henderson-Hasselbalch equation

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pH = 7.21 + log 0.225 / 0.162

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