Answer:
(See explanation for further information)
Explanation:
a) The distances of each planet with respect to the Sun is:
Mercury - 
Venus - 
Earth - 
Mars - 
Jupiter - 
Saturn - 
Uranus - 
Neptune - 
b) The solutions are presented below:
A. The distance between Venus and Jupiter is:


B. The combined distance from the Sun is:


Which is less than the distance from the Sun to Neptune (
).
C. The new distance of Earth is
(
). Saturn would be the closest planet to Earth, whose distance:
Scientific notation:


Standard notation:


Black and Whites were hungry and thirsty
Answer:
A) 100°C
B) 211 g
Explanation:
Heat released by red hot iron to cool to 100°C = 130 x .45 x 645 [ specific heat of iron is .45 J /g/K]
= 37732.5 J
heat required by water to heat up to 100 °C = 85 x 4.2 x 80 = 28560 J
As this heat is less than the heat supplied by iron so equilibrium temperature will be 100 ° C. Let m g of water is vaporized in the process . Heat required for vaporization = m x 540x4.2 = 2268m J
Heat required to warm the water of 85 g to 100 °C = 85X4.2 X 80 = 28560 J
heat lost = heat gained
37732.5 = 28560 + 2268m
m = 4 g.
So 4 g of water will be vaporized and remaining 81 g of water and 130 g of iron that is total of 211 g will be in the cup . final temp of water will be 100 °C.
Answer:
847.45 N
Explanation:
F₁=force of exerted by smaller piston
F₂=force of exerted by larger piston=1.44×10⁴ N
A₁=Area of smaller piston= 2.62 cm =0.0265 m
A₂=Area of larger piston= 10.8 cm =0.108 m
Pressure exerted by both the pistons will be equal

Hence, force exerted to lift a 14400 N car is 847.45 N
Answer:
240 Ω
Explanation:
Resistance: This can be defined as the opposition to the flow of current in an electric field. The S.I unit of resistance is ohms (Ω).
The expression for resistance power and voltage is give as,
P = V²/R.......................... Equation 1
Where P = Power, V = Voltage, R = Resistance
Making R the subject of the equation,
R = V²/P.................... Equation 2
Given: V = 120 V, P = 60 W.
Substitute into equation 2
R = 120²/60
R = 240 Ω
Hence the resistance of the bulb = 240 Ω