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Kay [80]
2 years ago
6

Can someone please answer this, ill give you brainliest Would be very appreciated.

Physics
2 answers:
N76 [4]2 years ago
7 0

Answer: A Because that is local I mean it is confined to a city at least i think so

Gnesinka [82]2 years ago
5 0

Answer:

Option 3

Explanation:

All of the mentioned options are mitigation solutions. But, the question has clearly asked for local solutions, which means it has the possibility or feasibility to take place in every neighborhood no matter where you are.

The option which correctly gives this is :

  • An individual elects to walk or bike to work daily
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An example of an unbalanced force is what
Nadya [2.5K]

Answer:

Any two forces acting on each other, which are not equal and opposite ( thereby causing motion ) are unbalanced forces.

Explanation:

Expierience

4 0
3 years ago
You are holding a positive charge and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east. Wh
lara [203]

If I hold a positive charge in my hand and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east then the direction of the force on the charge I am holding is towards the north-east direction.

Reasoning:

It is given that there is a positive charge in my hand. There are two more positive charges with the same magnitude. One is 1 mm far towards the east, and the other one is 1 mm far towards the north. It is required to find the direction of the force acting on the charge in my hand.

Let the magnitude of the charge in my hand is Q, and the magnitude of the other charges is q.

Thus the electric force applied on the charge in my hand due to each other is,

F=\frac{kQq}{r^2}

Here k is the Coulomb constant, and r is the distance between the charges.

It is also known that the force on a positive charge due to another positive charge is acted outwards.

Thus, the force on the charge due to the charge on the east is,

\vec{F_1}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{i}

And the force on the charge due to the charge on the north is,

\vec{F_2}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{j}

As the forces are equal in magnitude and one is perpendicular to the other, thus the net force will be acted at an angle of 45^\circ from the north or from the north direction.

Thus the net force is acting in the north-east direction.

Learn more about the direction of the force here,

brainly.com/question/2037071

#SPJ4

3 0
2 years ago
Dust settling out of the air<br> chemical change or physical change
mars1129 [50]
Physical changes: melting, evaporating, and condensation. This is a physical change.
7 0
3 years ago
Read 2 more answers
A swimmer of mass 64.38 kg is initially standing still at one end of a log of mass 237 kg which is floating at rest in water. He
nikklg [1K]

Answer:

0.9432 m/s

Explanation:

We are given;

Mass of swimmer;m_s = 64.38 kg

Mass of log; m_l = 237 kg

Velocity of swimmer; v_s = 3.472 m/s

Now, if we consider the first log and the swimmer as our system, then the force between the swimmer and the log and the log and the swimmer are internal forces. Thus, there are no external forces and therefore momentum must be conserved.

So;

Initial momentum = final momentum

m_l × v_l = m_s × v_s

Where v_l is speed of the log relative to water

Making v_l the subject, we have;

v_l = (m_s × v_s)/m_l

Plugging in the relevant values, we have;

v_l = (64.38 × 3.472)/237

v_l = 0.9432 m/s

8 0
3 years ago
L 1.3.5 Quiz: Using Models
arsen [322]

Answer:

0.12 is correct

Explanation:

1:25=1/25

1/25x3=

3/25=0.12:)

8 0
3 years ago
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