Yes it is possible because, olymorphismis when two or more crystal structures are possible for a material of given composition. Isomerismis when two or more polymer molecules or repeat units have the same composition, but different atomic arrangements.
Answer:
Molecular formula = C₂H₄Cl₂
Explanation:
Molecular formula:
Molecular formula consist of symbols of elements present in compound with numbers of atoms of each element in subscript.
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number .
Given data:
Percentage of hydrogen = 4.07%
Percentage of Cl = 71.65%
Percentage of carbon = 24.27%
Molar mass = 99 g/mol
Molecular formula = ?
Solution:
Number of gram atoms of H = 4.07 / 1.01 = 4.0
Number of gram atoms of Cl = 71.65 / 35.5 = 2.0
Number of gram atoms of C = 24.27 / 12 = 2.0
Atomic ratio:
H : C : Cl
4/2 : 2/2 : 2/2
2 : 1 : 1
C : H : Cl = 1 : 2 : 1
Empirical formula is CH₂Cl.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = 12+1×2+ 35.5 = 49.5
n = 99/49.5
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 ( CH₂Cl)
Molecular formula = C₂H₄Cl₂
Fawn spends hours each week managing employee shifts and schedules, time she should be spending on other restaurant operations. What can she do? O a) Start leaving more time in her week for scheduling-related tasks b) Write everything down in a weekly planner O c) Consider online inventory management software O d) Consider online scheduling software
Answer:
45.7kj
Explanation:
To calculates the heats of reaction from heats of formation:
∆Hr=£∆Hp -£∆Hr
= £∆Hch3ChOH - £∆HCh2h2+h20
=(-235.1kj)-(+52.47kj/kg + (-241.8kj/kg)
∆H = 45.71kj/kg
Answer:
Percentage mass of copper in the sample = 32%
Explanation:
Equation of the reaction producing Cu(NO₃) is given below:
Cu(s)+ 4HNO₃(aq) ---> Cu(NO₃)(aq) + 2NO₂(g) + 2H₂O(l)
From the equation of reaction, 1 mole of Cu(NO₃) is produced from 1 mole of copper. Therefore, 0.010 moles of Cu(NO₃) will be produced from 0.010 mole of copper.
Molar mass of copper = 64 g/mol
mass of copper = number of moles * molar mass
mass of copper = 0.01 mol * 64 g/mol = 0.64 g
Percentage by mass of copper in the 2.00 g sample = (0.64/2.00) * 100%
Percentage mass of copper in the sample = 32%
