Answer:
C. 0.4.
Explanation:
<em>∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).</em>
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- no. of moles of acetic acid = 2, no. of moles of water = 3.
- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.
<em>∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) =</em> (2)/(5)<em> = 0.4.</em>
All of them are matter tho
Answer:
4,2,1,3
Explanation:
4. A small ribosomal subunit binds to a molecule of mRNA5. the anticodon of an incoming aminoacyl tRNA base-pairs with the complementary mRNA codon in the A site.
2. The large ribosomal subunit attaches with the initiator tRNA with the amino acid methionine (Met) located in the P site.
1. The ribosome translocates the tRNA in the A site to the P site and the empty tRNA in the P site is moved to the E site where it is released.
3. A release factor, a protein shaped like an aminoacyl tRNA, promotes hydrolysis and releases the polypeptide.
<span>Platinum is solid at room temperature. SInce the catalyst is solid while the medium involves gases, this catalyst is characterized as heterogenous. Because they are different states of matter, they can be easily separated through physical means. So, the answer is B.</span>
The molarity of a solution that contains 20.0grams of sodium hydroxide in 200. ml of solution is 2.3 M.
<h3>What is Molarity? </h3>
Molarity is defined as the ratio of number of moles of solute to the volume of the solution.
Molarity = number of moles of solute/ Volume of solution
Given,
given mass of sodium hydroxide= 20 g
Volume of the solution = 200 mL.
Firstly, we will calculate the moles of sodium hydroxide.
<h3>What is Mole? </h3>
Mole is defined as the ratio of given mass of substance to the molar mass of substance.
Mole = given mass/ molar mass
Molar mass of sodium hydroxide = 40 g
Mole = 20/40
= 0.5 mol
Molarity = (0.5/ 200) × 1000 = 2.5M
Thus, we calculated that the molarity of a solution that contains 20.0grams of sodium hydroxide in 200. ml of solution is 2.3 M.
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