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Nady [450]
2 years ago
5

An inductor connects to an AC circuit. If the frequency of the AC oscillations decreases, does the inductance increase, decrease

, or remain constant?
Physics
1 answer:
ASHA 777 [7]2 years ago
7 0

Answer:

The inductance remains constant

Explanation:

The inductance value remains constant because it is a intrinsic property of an inductor. Its value depends on physical characteristics and dimensions like length, number of turns, etc.

What changes is the impedance of the inductance. Now, the impedance does changes with the frequency of the AC signal. The relations is as follows:

Z = jωL, where Z is the impedance, j is the imaginary unit, ω is the angular frequency, and L is the inductance.

In terms of frequency ω=2π·f, where f is the frequency of the signal.

So, the impedance in terms of f is:

Z = j·2·π·f·L

If f decreases, the value of the Z decreases too, because if f has a lower value and the other terms remain constant, the value of Z will be lower.

So, the inductance remains constant.

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kvasek [131]

Answer:

The maximum electric field strength = 0.01 V/m

Explanation:

Given

ΔV(max) = 4.00 mV = 0.004 V

d = 0.400 m

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Maximum electric field = (maximum potential)/(length)

Maximum electric field = E(max)

Maximum potential = 4.00 mV = 0.004 V

Length = 0.400 m

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Hope this Helps!!!

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2 years ago
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<span>This applies to trumpets, violins, flutes and a broad range. </span>
<span>In such a </span>case<span> the first harmonic would be at n=1 and the second harmonic would be at n=2 </span>

<span>which gives a frequency of 84 Hz</span>
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The moon's mass is 7.34x10-kg and it is 3.8x10m away from earth. Calculate the gravitational force of attraction between earth a
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Again I think you did not give the right constants. So I would use the correct constants for mass of moon and distance from earth to moon.

<span>The formula for force of attraction between any two bodies in the universe
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G = Universal gravitational constant, G = 6.67 * 10 ^ -11  Nm^2 / kg^2.
M = Mass of Earth. = 5.97 x 10^24 kg.
m = mass of moon = 7.34 x 10^22  kg.
r = distance apart, between centers = in this case it is the distance from Earth to the Moon
   = 3.8 x 10^8 m.

(Sorry I could not assume with the values you gave, they are wrong, and if we use them we would be insulting Physics).


So F = ((6.67 * 10 ^ -11)*(5.97 x 10^24)*(7.34 * 10^22)) / (3.8 x 10^8)^2.
  Punch it all up in your calculator.
 
I used a Casio 991 calculator, it should be one of the best in the world.Really lovely calculator, that has helped me a lot in computations like this. I am thankful for the Calculator.

F = 2.0240 * 10^ 20 N.
So that's our answer.
Hurray!!</span>




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Explanation:

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