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Tema [17]
3 years ago
5

How much horse power do you think a Dodge Challenger hellcat has?

Engineering
2 answers:
Elenna [48]3 years ago
8 0

Answer:

round 800

Explanation:

ArbitrLikvidat [17]3 years ago
4 0

Answer:

Its prob around 700

Explanation:

You might be interested in
Exercise 19
musickatia [10]
Uhh idk this can u mabye look it up
6 0
3 years ago
You recall an algorithm from elementary school for factoring a number N: Divide out all factors of 2, then of 3, then of 4, then
Contact [7]

Answer:

let number = 0

while number < 1

  begin

     print "Enter a positive integer: "

     read number

  end

end_while

find and print number's factors:

let prime = TRUE

let currentFactor = 2

let lastFactor = the square root of number truncated

  to an integer value

while currentFactor <= lastFactor

  begin

     if number is evenly divisible by currentFactor

        begin

           print currentFactor

           let number = number / currentFactor

        end

     else

        let currentFactor = currentFactor + 1

     end_if

  end

end_while

print a message if number is prime:

if prime == TRUE

  print "Your number is prime"

end_if

Explanation:

4 0
3 years ago
At high altitudes, mountaineers cannot absorb a sufficient amount of O2 in your flows blood to maintain a high level of activity
Free_Kalibri [48]
What’s the question?
3 0
3 years ago
Integrate <br>∫cos²x sinx dx<br>​
Marianna [84]

Answer:

-⅓ cos³ x + C

Explanation:

∫ cos² x sin x dx

If u = cos x, then du = -sin dx.

∫ -u² du

Integrate using power rule:

-⅓ u³ + C

Substitute back:

-⅓ cos³ x + C

3 0
4 years ago
7 A very large thin plate is centered in a gap of width 0.06 m with different oils of unknown viscosities above and below; one v
sineoko [7]

Answer:

\mu_1\approx 0.967

\mu_2\approx 1.933

Explanation:

The viscosities above and below the plate are given by

\mu_2=2\mu_1 where \mu_1 and \mu_2 are viscosities of fluid below and above plate respectively

Force on plate due to top layer of the fluid

\tau_1=\mu_1\frac {\triangle u}{\triangle y} where \triangle u and \triangle y are the velocity of plate and gap between the plate and upper surface respectively.

\tau_1=\mu_1\times \frac {0.3}{0.03}=10\mu_1

Force on plate due to bottom layer of the fluid is given by

\tau_2=\mu_2\frac {\triangle u}{\triangle y} where \triangle u and \triangle y are the velocity of plate and gap between the plate and upper surface respectively

\tau_2=\mu_2\times \frac {0.3}{0.03}=10\mu_2

Total force per unit area is the sum of two shear forces

\frac {F}{A}=\tau_1 +\tau_2 hence

\tau_1+\tau_2=29

10\mu_1+10\mu_2=29

10(\mu_1+\mu_2)=29

\mu_1+\mu_2=2.9 but since \mu_2=2\mu_1 hence

\mu_1+2\mu_1=2.9

3\mu_1=2.9

\mu_1=\frac {2.9}{3}=0.966667\approx 0.967

\mu_2=2\mu_1=2*0.966667=1.933333\approx 1.933

8 0
3 years ago
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